a=change over velocity/time
60-initial velocity
45-final velocity
45-60= 15m/s
15/5= 3- acceleration
The average acceleration is given by the expression a ∆v/∆t (15 m/s)/5s 3m/s2 where a is acceleration, v is velocity, and t is time. ∆ (final-initial) value.
5 hours and 4 seconds or 304 seconds
There are 60 seconds in a minute, and 60 minutes in an hour, so there are 60^2 = 3600s in an hour. There are 24 hours in a day, so there are 3600*24 = 86,400 seconds in a day. There are 365 days in a normal year, so there are 86,400*365 = 31,536,000 seconds in a year. There are 366 days in a leap year, so there are 31,622,400 seconds in a leap year. Scientifically seen, there are c. 365.25 days in a year, so in an actual year (scientifically seen) there are 31,557,600 seconds in a year.
It depends, but the average is usually between 20 to 30 seconds.
With great difficulty. This is because if the variable is recorded by people, it will be rounded. That process will make it discrete - even if the underlying variable is continuous.For example, time is a continuous variable, but time is normally recorded in seconds. At track events it may be measured in hundredths of seconds and in some labs in much smaller units. Nevertheless it will always be in discrete "chunks".
Yes, velocity is acceleration x time. If acceleration is the same, velocity can be different as it changes with time. For example a car accelerating with constant acceleration will have a different velocity after 5 seconds than it will have at 2 seconds.
Acceleration occurs when velocity changes over time. The formula for it is as follows: a = (Vf - Vi) / t a: acceleration (meters/seconds2) Vf: Final velocity (meters/seconds) Vi: Initial Velocity (meters/seconds) t: Time (seconds)
zero
2 meter/seconds squared
what is the change in speed or velocity? average acceleration will be change in speed or velocity divided by time taken (4 seconds in ur case)
Rule: Magnitude of acceleration = Change of velocity / Time interval In linear motion, magnitude of acceleration is the measurement of change in speed in speed per unit time. For example: A car reaches a speed of 20 miles per second in 4 seconds, the magnitude of acceleration is 5 miles per second. a = 20 miles/second divided by 4 seconds = 5 miles per second. Acceleration is a vector, which means it has magnitude and direction. To describe accelerated motion completely, the direction also needs to be included. So it would be 5 miles per second in whatever direction it is going.
3 ms-2
Acceleration= distance / velocity squared
Magnitude of average acceleration = (change of speed) divided by (time for the change)Average 'A' = (6 - 4) / 20 = 2/20 = 0.1 meter per second2-- That's the average over the 20 seconds. We don't know anything about thevalue of the acceleration at any particular instant during the 20 seconds.-- We're working entirely with scalars ... speed, not velocity, and magnitude ofacceleration ... since we don't know anything about the runner's direction atany time during the whole event.
Magnitude of average acceleration = (change of speed) divided by (time for the change)Average 'A' = (35 - 65) / 10 = -30/10 = -3.5 meters per second2-- That's the average over the 10 seconds. We don't know anything about thevalue of the acceleration at any particular instant during the 10 seconds.-- We're working entirely with scalars ... speed, not velocity, and magnitude ofacceleration ... since we don't know anything about the arrow's direction at anytime during the whole event.
If velocity is steady and doesn't change, then there is 0 acceleration.
That depends on its initial velocity and its acceleration. V1 = V0 + a * t