It is 2/13.
There are 12 face cards in a standard deck of 52 cards; the jacks, queens, and kings of spades, diamonds, clubs, and hearts. The probability, then, of drawing a face card is 12 in 52, or 3 in 13, or about 0.2308.
It is 0.000181, approx.
This problem is the type of the probability of A and the probability of B. These events are independent. P(A) and P(B) = P(A) * P(B). In this case these two probabilities are equal; the probability of a king is 4/52. So, the probability of draw king, replace and draw king is 4/52 * 4/52 = 0.00592.
There are 4 Kings in a standard pack of 52 cards. If 1 King has previously been drawn this now leaves 3 kings out of a total of 51 remaining cards. The probability of now drawing a King is therefore 3/51 which simplifies to 1/17. Note: this is the probability concerning the 2nd draw only.
There are four kings and four queens in a standard 52 card deck. The probability, then, of drawing a king or a queen is 8 in 52, or 2 in 13, or about 0.1538.
There are 12 face cards in a standard deck of 52 cards; the jacks, queens, and kings of spades, diamonds, clubs, and hearts. The probability, then, of drawing a face card is 12 in 52, or 3 in 13, or about 0.2308.
A standard 52 cards deck contains 4 kings and 4 tens. Given that the type of the card does not matter, we have a total of 8 valid cards (4 kings + 4 tens) to choose from a 52 cards deck. Hence the probability is 8/52.
The probability of drawing two kings from a standard deck of 52 cards is (4 in 52) times (3 in 51), or 12 in 2652, or 1 in 221, or about 0.004525.
That is a rather hard question to answer. It would really depend on how many cards you have in the deck and how many jacks and kings you have Ex: If you had 30 cards and 5 jacks and kings then the probability would be 10/30 or 1/3
It is 0.000181, approx.
This problem is the type of the probability of A and the probability of B. These events are independent. P(A) and P(B) = P(A) * P(B). In this case these two probabilities are equal; the probability of a king is 4/52. So, the probability of draw king, replace and draw king is 4/52 * 4/52 = 0.00592.
4 kings in 52 cards then 3 kings in 51 cards 4/52 * 3/51 = .00452488
There are 4 Kings in a standard pack of 52 cards. If 1 King has previously been drawn this now leaves 3 kings out of a total of 51 remaining cards. The probability of now drawing a King is therefore 3/51 which simplifies to 1/17. Note: this is the probability concerning the 2nd draw only.
The probability of choosing a king from a standard deck of playing cards is 4 out of 52, or 1 out of 13. This is because there are 4 kings (one each of hearts, diamonds, clubs, and spades) in a deck of 52 cards.
The probability depends on:whether the cards are drawn randomly,how many cards are drawn, andwhether the cards are replaced before drawing the next card.If only 2 cards are drawn randomly, and without replacement, the probability is 0.00075 approximately.
There are four kings and four queens in a standard 52 card deck. The probability, then, of drawing a king or a queen is 8 in 52, or 2 in 13, or about 0.1538.
The probability of drawing a king on the first draw is 4/52 = 1/13. The probability that the next card is one of the 3 remaining kings is 3/51 = 1/17. The probability of both events is (1/13)*(1/17) = 1/221