There are 12 face cards in a standard deck of 52 cards. The odds of the first card being a face card is 12/52. If the first card drawn is a face card then there are 11 face cards remaining in the deck of 51 cards. The odds of a second draw of a face card is then 11/51. If both the first two cards drawn were face cards then the deck has 10 face cards in 50 total card. The odds of the third card also being a face card is 10/50. The total probability is (12/52)*(11/51)*(10/50) = 0.009954751 or just under one percent of the time.
The probability of drawing aces on the first three draws is approx 0.0001810
hypergeometric distribution f(k;N,n,m) = f(3;52,4,3)
The probability of rolling a six is one in six. The probability of rolling three consecutive sixes is one in 216. (1/6 x 1/6 x 1/6 = 1/216)
The probability of drawing three black cards one at a time with replacement from a standard deck of 52 cards is 1/3x1/2x26/52, which is 0.833.
The probability of drawing the first ace is 4 in 52. The probability of getting the second ace is 3 in 51. The probability of getting the third ace is 2 in 50. The probability, then, of drawing three aces is (4 in 52) times (3 in 51) times (2 in 50), which is 24 in 132600, or 1 in 5525, or about 0.0001810
The probability of drawing aces on the first three draws is approx 0.0001810
(3/7)*(2/7)=(6/49) You have a 6 out of 49 probability.
hypergeometric distribution f(k;N,n,m) = f(3;52,4,3)
The probability of rolling a six is one in six. The probability of rolling three consecutive sixes is one in 216. (1/6 x 1/6 x 1/6 = 1/216)
whats the probability that three times in a row without looking i can pick out an outmeal cookie without replacing them?
The probability of drawing three black cards one at a time with replacement from a standard deck of 52 cards is 1/3x1/2x26/52, which is 0.833.
The probability of drawing the first ace is 4 in 52. The probability of getting the second ace is 3 in 51. The probability of getting the third ace is 2 in 50. The probability, then, of drawing three aces is (4 in 52) times (3 in 51) times (2 in 50), which is 24 in 132600, or 1 in 5525, or about 0.0001810
There are 6!/3! = 120 possible combinations of marble colour. Of these, only 2 are "good". This gives a probability of 2/120 = 1/60 = 0.0167, or about one and two-thirds of a percent.
The probability of picking ABC, in that order, from 5 A's, 3 B's, and 2 C's, without replacement, is (5 in 10) times (3 in 9) times (2 in 8), or 30 in 720, or 3 in 72, or 1 in 24.
The probability is 1 if you draw three balls without replacement. If only one draw, it is 3/5.
1/26
The probability of drawing two blue cards froma box with 3 blue cards and 3 white cards, with replacement, is 1 in 4, or 0.25.The probability of drawing one blue card is 0.5, so the probability of drawing two is 0.5 squared, or 0.25.