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In a bag there are 3 red marbles and B blue marbles. Two marbles are randomly selected from the bag without replacement. The probability that the two marbles are the same color is 0.5. What is the sum?
7
What is the probability of pulling a red marbles out of a bag containing 16 red marbles 10 green marbles 14 blue marbles and 10 yellow marbles?
If you pull 35 marbles without replacement, the answer is 1: the event is a certainty. If you pull only one marble, at random, the probability is 16/50 = 8/25.
If you have a bag of 4 red and 4 green marbles what is the probability of drawing 2 marbles without replacement and getting 2 green marbles?
4/8 or 1/2(probability of first draw) * 3/8(probability of second draw which is 12/64 or 3/16 of the given scenario.
A container holds 6 red marbles and 4 green marbles You select 2 marbles from each container without replacement What is the probability that you will select 1 red marble and 1 green marble?
sure chance
What does without replacement mean in probability?
Im not good at explaining things but here's an example. If I have 5 red marbles and 6 blue marbles in a bag and I pick one out. I then choose another marble without returning the first marble to the bag. Hope this helps.
In a bag there are 3 red marbles and B blue marbles. Two marbles are randomly selected from the bag without replacement. The probability that the two marbles are the same color is 0.5. What is the sum?
7
You have 12 marbles 8 are blue 4 are green what is probability one of each color is chosen on the first two draws?
If the two marbles are drawn without replacement, the probability is 16/33.
What is the probability of pulling a red marbles out of a bag containing 16 red marbles 10 green marbles 14 blue marbles and 10 yellow marbles?
If you pull 35 marbles without replacement, the answer is 1: the event is a certainty. If you pull only one marble, at random, the probability is 16/50 = 8/25.
If you have a bag of 4 red and 4 green marbles what is the probability of drawing 2 marbles without replacement and getting 2 green marbles?
4/8 or 1/2(probability of first draw) * 3/8(probability of second draw which is 12/64 or 3/16 of the given scenario.
A container holds 6 red marbles and 4 green marbles You select 2 marbles from each container without replacement What is the probability that you will select 1 red marble and 1 green marble?
sure chance
A bag contains 5 green marbles 3 yellow and 2 red marbles. What is the probability of picking three green marbles from the bag without replacement?
To find the answer to probability, first add all the things together (5+3+2=10), then, find the number of things you will be taking from the group of things (3), and put together as a fraction (3/10). So the final answer is 3/10, which is unlikely. :D
A bag contains 3 blue marbles and 4 red marbles. What is the probability that three randomly drawn marbles without replacement will all be red?
The probability of drawing 3 red marbles in a row from a bag of 3 blue and 4 red marbles without replacement is right at about 0.11 or about 11 in 100, if you want odds.Remember that probability is a pure number between zero (no chance - it's impossible) and 1 (it will happen - it's a certainty). A probability of 0.5 is a 50-50 shot, like a coin toss. We good? Let's move on.We have 7 marbles, and there is a 4 in 7 shot of getting a red marble in the first draw. There is a 3 in 6 shot the next draw since now we only have 6 marbles total (NO replacement) and only 3 red ones (we already drew a red one out). Similarly, there is a 2 in 5 shot of getting a third red one if the first two are red. The probability of the first action (getting a red marble on the first draw) is 4/7 or a probability of about 0.5714. Second draw, it's 3/6 or a probability of 0.5. Last, it's 2/5 or a probability of 0.40. To find the intersection of these probabilities, we just multiply them all together, and we'll get right at about 0.011 for a probability.
A box contains 3 white 5 red 2 green and 4 blue marbles two marbles are drawn without replacement what is the probibality of drawing two red marbles?
I believe it would be 5 red marbles of 14 total marbles (5/14)
What does without replacement mean in probability?
Im not good at explaining things but here's an example. If I have 5 red marbles and 6 blue marbles in a bag and I pick one out. I then choose another marble without returning the first marble to the bag. Hope this helps.
A bag has 7 blue marbles and 8 purple marbles.What is the probability of picking a blue marble then a purple marble without replacing?
7/15 for blue marbles and 8/14 for the purple marbles this is dependent probability
What is the probability of 6 green marbles?
We can't answer that without knowing what else is in the bowl.
A jar contains three colored marbles 10 red 15 green and 25 blue If you were to choose without looking what is the probability of selecting a blue marble?
25/50 gives the probability of selecting a blue marble
