they are all equally likely, just like flipping a coin.
#7
Seven - there are more ways to make seven than there are to make any other number.
The chance of rolling a certain number on a dice is 1/6, so the chance of rolling a 4 OR 5is 2/6. But if you have two dice you have the most chance of rolling a seven (6/36 or 1/6)
since there are 6 sides to it any of them could show up, 1,2,3,4,5, and 6 could all show up unlikely
The most common number would be 10 and 11. When using 3 dice, the total sum of eyes must be between 3 and 18. The most probably number being rolled can be found simply by calculating the average of the highest and lowest possibilities. (3+18)/2 = 10,5 ; meaning 10 and 11 are the two most probable numbers to be rolled using 3 dice.
they are all equally likely, just like flipping a coin.
#7
Regular craps is played with 2 dice, but most casinos keep 5 dice on the table and the 3 the shooter isn't using are kept in a bowl.
AnswerThe most likely number is seven.This can be 1+6, 2+5, 3+4, 4+3, 5+2, 6+1.Remember that dice have no memory - if you have rolled 7 three times in a row the odds of rolling another 7 does not change.this is all wrong don't listen that
-19
Ten-sided dice are often used in games that require a "percentage roll", such as Dungeons & Dragons. Players roll two 10-sided dice, and the numbers rolled are used as digits to form a number between 0 and 99. Using a "0" instead of "10" simplifies this process. For most other games and instances, zeroes on ten-sided dice represent tens. Just FYI - some ten-sided dice do actually have a "10" instead of a "0", but they're fairly rare. I got 4 of them in a board game called Filthy Rich, which - ironically enough - uses numerous references to rolling zeroes instead of tens. Go figure.
because most dice only have numbers 1 to 6 on them
all numbers on a die have the same probability to land so any number between 2 and 12 are just as likely as any other number between 2 and 12, just as any other die hase the same probability 2 d20, 2-40 any to are just as likely as the rest. so 0 is the least likely number. Well, yes, since 0 is impossible to be the sum of 2 dice, it is least likely. So is any other number less than 2 or greater than 12, or a number that is not a whole number. But of those that actually can come up as the sum of 2 dice, 7 is the most likely because there are 6 ways to get it (1 and 6, 2 and 5, 3 and 4, 4 and 3, etc.). The least likely sums are 2 and 12, because each can only occur 1 way (a pair of 1's or a pair of 6's). These are referred 2 by gamblers as snake eyes and box cars.
Seven - there are more ways to make seven than there are to make any other number.
Answer 1:The odds are very easy to calculate. Simply divide the number of "valid" rolls against all possible rolls. For ease, you can write down all possible combination for the 2 dice.1-1; 1-2; 1-3; 1-4....and so on, remember 1-4 and 4-1 are different rollsThere are 36 unique possible combination, and 6 of them are doubles, so that's 6/36 chances (and since 6 goes into 36, 6 times, this reduces to 1/6) or about 17%Answer 2:Another way to look at this problem, generically, is to assume we have an 'n' face dice. In most cases, dice have 6 faces (1, 2, 3, 4, 5, 6). But why not create a solution that works for any number of sides? Well, if we are trying to calculate the probability of rolling two dice (dice-1 and dice-2) of 'n' sides at the same time and having them turn up as doubles, only one of the dice really matters. Here's why. Dice-1 is guaranteed to land on a number 1-n. This will happen every time (on a fair dice, disregarding freak incidents). What we are trying to calculate is the probability that dice-2 will land on the SAME number as dice-1. Dice-2 can only land on one of 'n' values: 1, 2, 3, 4, 5, 6, ... , 'n'. For you non math folks, this just means it must land on a number from 1 to 'n' where 'n' is the number of sides on your dice. Out of all of the sides that dice-2 can PHYSICALLY land on, one of the sides MUST necessarily have the same as the value that dice-1 landed on. That is to say, if dice-1 landed on the value 3, there must be some chance that dice-2 will also land on the value 3. The probability of this occurring on a fair die is 1 divided by the total number of possible outcomes, which would be 'n'. So, really, there is a 1/n chance that dice-2 will land on the same number as dice-1. Thus, our probability for rolling doubles is simple 1/n. For our 6 sided dice example, our dice-1 lands on some value between 1 and 6 and there is a 1/6 chance dice-2 will match it.
In the game of Craps, you have two dice and bet on which number comes up. There are more possibly ways to make a seven then any other number therefore 7 is the number to bet on.