They are experimentally determined exponents.
It is simply a straight line equation in the form of: y = mx+c whereas m is the slope and c is the y intercept
It is the graphical representation of a linear relationship between two variables. In its most general form, the relationship is of the form a1x1 + a2x2 + ... + anxn + c = 0 where x1, x2 etc are variables, and the as are constants. This equation would be a straight line in n-dimensional space. In 2-dimensional space, and renaming the variables, you get ax + by + c = 0 where x and y are the variables and a, b and c are constants. This equation can be expressed in the form y = mx + d where m and d are constants. m is called the slope or gradient. For every increase of 1 unit in x, you will get an increase of m units in y. Also, d is called the intercept and it represents the value of y when x is 0.
there are 1,000 m and m's
No, M&M's are better because they contain chocolate.
over 1,000,000 $ of m&m's are collected i thenk O_o
5.4 (apex)
The rate of the reaction can be calculated using the rate law equation rate = k[A]^m[B]^n. Plugging in the given values k = 0.2, m = 1, n = 2, [A] = 3 M, and [B] = 3 M into the equation gives rate = 0.2 * (3)^1 * (3)^2 = 16.2 M/s.
4.5 (mol/L)/s
The rate of the reaction can be calculated using the rate law rate = k[A]^m[B]^n. Plugging in the given values: rate = 0.02*(3)^3*(3)^3 = 0.022727 = 14.58 M/s.
Rate = k[A]m[B]n
They are experimentally determined exponents
r=[A]m[B]n APPLEX
To write a rate law for a chemical reaction, one must determine the order of the reaction with respect to each reactant by conducting experiments and analyzing the rate of reaction at different concentrations. The rate law is then expressed as rate kAmBn, where k is the rate constant, A and B are the concentrations of the reactants, and m and n are the orders of the reaction with respect to each reactant.
The rate law equation, which is usually in the form: rate = k[A]^m[B]^n, shows how the rate of a reaction depends on the concentrations of reactants A and B. Here, k is the rate constant, [A] and [B] are the concentrations of the reactants, and m and n are the respective reaction orders.
The rate constant must have units that make the rate equation balanced. For example, if the rate law is rate kA2B, the rate constant k must have units of M-2 s-1. To calculate the rate constant, you can use experimental data and the rate law equation to solve for k.
The rate of the reaction is calculated using the rate equation: rate = k[A]^3[B]^2. Given k = 0.01, [A] = 2 M, and [B] = 3 M, the rate can be determined by substituting these values into the rate equation and solving for the rate.
True