If you assume that the Ace is high, then the odds of drawing a card higher than a nine is a standard deck of 52 cards is 20 in 52, or 5 in 13, or about 0.3846. If you assume that the Ace is low, then the odds of drawing a card higher than a nine is a standard deck of 52 cards is 16 in 52, or 4 in 13, or about 0.3077.
8 out of 32
The probability of drawing one face card is 12 in 52. The probability of drawing the second face card, then, is 11 in 51. And so on, 10 in 50, 9 in 49, and 8 in 48. Since this is sequential probability, simply multiply the odds, giving (12/52)(11/51)(10/50)(9/49)(8/48) or (95040/311875200). I'l leave it to the reader to do the simple reduction to lowest terms.
This would be like drawing a spade (or any suit for that matter) from a deck of cards one-by-one. Probability is: 13/52*12/51*11/50*10/49*9/48*8/47*7/46*6/45*5/44*4/43*3/42*2/41*1/40 = 6227020800/3.95424E21= 1.57477E-12= 0+
The answer depends on drawing a 9 from WHAT!
There are four nines in the deck of fifty two cards. Therefore your odds are 4 out of fifty two, or one out of thirteen. (4/52 = 1/13) chances of drawing a nine. The odds, then, of not drawing a nine is 48/52, or 12/13, or about 0.9231.
If you assume that the Ace is high, then the odds of drawing a card higher than a nine is a standard deck of 52 cards is 20 in 52, or 5 in 13, or about 0.3846. If you assume that the Ace is low, then the odds of drawing a card higher than a nine is a standard deck of 52 cards is 16 in 52, or 4 in 13, or about 0.3077.
The probability of drawing 3 cards, all with the value of 9, from a standard 52 card deck, is ~0.018%.
If you don't specify the color, there are four of each card. So out of 52 cards there are four nines. Four out of 52 can be simplified into 1/13, which is about 8%.
There are four 9's and 48 non-9's. The odds against a 9 is 48 to 4.
8 out of 32
4/52 or 1/13 or 0.0769.
The probability of drawing a king or a nine from a standard deck of 52 cards is (4 + 4) in 52, or 8 in 52, or 2 in 13, or about 0.1538.
It is 2/13.
The wording of your question is such that it can mean three completely different things:"What chance do you have of drawing a card that can be used as a 9 of hearts with two jokers in the deck?""What chance do you have of drawing the 9 of hearts from a full deck that contains two jokers (54 cards)?""What chance do you have of drawing the 9 of hearts and both jokers"In answer to each of those questions:3/54 = 1/181/541/54 × 2/53 × 1/52 = 2/148824 = 1/74412
The probability of drawing one face card is 12 in 52. The probability of drawing the second face card, then, is 11 in 51. And so on, 10 in 50, 9 in 49, and 8 in 48. Since this is sequential probability, simply multiply the odds, giving (12/52)(11/51)(10/50)(9/49)(8/48) or (95040/311875200). I'l leave it to the reader to do the simple reduction to lowest terms.
This would be like drawing a spade (or any suit for that matter) from a deck of cards one-by-one. Probability is: 13/52*12/51*11/50*10/49*9/48*8/47*7/46*6/45*5/44*4/43*3/42*2/41*1/40 = 6227020800/3.95424E21= 1.57477E-12= 0+