The odds are... remote. This is a factorial problem to calculate the answer you take how many options the first "dealt" card has of being. In this case the first card has a 1-in-52 chance of being the Ace of Spades (the "highest" card in a deck.) The next card has a 1-in-51 chance of being the Two of Spades, and so on. You calculate the odds of this happening my multiplying 52 by 51.
So, the odds are 52 times 51 times 50 times 49 times 48 times... yadda yadda yadda until you get to one. The answer?
The odd of taking a shuffled deck of cards, reshuffling it, and the dealing the cards back in the correct order are 1 in 806,581,751,709,439x10 to the 54th power. (septendecillion.)
Or 80 unvigintillion. (80 followed by 66 zeroes). For the sake of comparison, conservative estimates put the number of stars in our galaxy at 100 Billion (100 followed by 9 zeroes) and the number of galaxies in the universe at the same number, making the number of potential stars in the universe at 10 sextilion (a 10 followed by 21 zeroes.)
It depends on what exactly the conditions are. If you mean from a 52 card deck, drawing one card right after the other, then the chance that they will be those two cards in that exact order is 1/52 * 1/51. This is pretty much a percent of a percent. .00038, or about 4 percent of a percent.
The answer will depend on the exact situation.If you are dealt a single card, the probability of that single card not being a queen is 12/13 - assuming you have no knowledge about the other cards.Here is another example. If you already hold three queens in your hand (and no other cards have been dealt), the probability of the next card being dealt being a queen is 1/49, so the probability of NOT getting a queen is 48/49 - higher than in the previous example.
Often a quick estimate is better. The population of a city for example. An exact answer would require a lot of time and money, and by the time you got your answer, people would have moved in or out, changing the exact answer.
Estimation
becaused it is exact
No you cant
That really depends upon what your name is.
I Don't know the exact number but a lot of newly released games have about 2800 cards on them and they don't even have all the cards in the game. There are definitly 2800+ cards in the game.
I don't know the exact chances, but it's certainly possible, so you should take a pregnancy test.
"There are not really any advantages or using CFd dealing. It is pretty much the exact same as using any other dealer. However, CFd's can be less expensive with lower margins."
Many of the hockey cards are valued in price close to $1 each. The exact amount for the cards will vary depending upon their condition.
I cannot give you the exact date but these cards are valuable in any generation:Babe RuthMickey MantleTy CobbHonus WagnerEddie PlankLou GehrigJoe JacksonJoe Doyle
Any where from about 7 to 200,000. If you are dealing with premium BKC it's about 12.
The probability of being dealt a 3 pair in Texas Hold'em is very low, as it is a rare hand in the game. The exact probability depends on the number of players at the table and the specific cards in play, but generally speaking, the chances of being dealt a 3 pair are slim.
You have to follow the movement of the tile as it is shuffled around. It is sometimes difficult but with practice you can pick it out easily.(If you can't see where it is moving, try picking the exact same position for 8 or 9 games and eventually you just get lucky and it is there.)
I dont know the exact number, but writing paid off for me, i got a letter from him back just recently!
I am wondering the same exact thing! someone please answer