The probability of getting an odd number in a single throw of a fair die (not dice!) is 1/2.The probability of getting an odd number in a single throw of a fair die (not dice!) is 1/2.The probability of getting an odd number in a single throw of a fair die (not dice!) is 1/2.The probability of getting an odd number in a single throw of a fair die (not dice!) is 1/2.
There are 6 outcomes on a die roll (1,2,3,4,5,6); 5 & 6 constitutes 2 of them so the probability is 2/6 or 1/3.
The complement of rolling a die and getting a 4 is rolling a die and getting a 1, 2, 3, 5, or 6.
When you throw a fair dice you have an equal possibility of getting 1, 2, 3, 4, 5 or 6. If you want to get a number greater than 4 this means you want 5 or 6: the probability is 2/6, which can be simplified to 1/3.
This can be calculated easily by multiplying the chances of getting one head in one toss for a fair coin (half) by itself(half) to give a quarter (1/4 or 1 in 4). If you wanted the chances of at least one head in 2 tosses, then the chances would be for anyhting exept 2 tails in a row, which is 1 - 0.25(quarter), which is 0.75 (3/4 or 3 quarters or 3 in 4)
The probability of getting an odd number in a single throw of a fair die (not dice!) is 1/2.The probability of getting an odd number in a single throw of a fair die (not dice!) is 1/2.The probability of getting an odd number in a single throw of a fair die (not dice!) is 1/2.The probability of getting an odd number in a single throw of a fair die (not dice!) is 1/2.
When you throw a dice there is always 6 chances of getting a number; therefore the numbers greater that 4 are: 5 and 6 (2 options) in total there will be 2/6 chances will simplifies to 1/3
"The probability of getting a prime number in a die is 4/6" Actually there are 3 prime numbers on a die. 2, 3, and 5 are all prime numbers. So this tells you that you have 3 chances it will be a prime number and 3 chances it will not be a prime number. So the probability of getting a prime number on a die would be 3/6 or 1/2.
6 chances Actually, it is 1/4. Chances of an even number on the first die are 1/2, and chances on the second die are 1/2; 1/2 x 1/2 = 1/4
There are 6 outcomes on a die roll (1,2,3,4,5,6); 5 & 6 constitutes 2 of them so the probability is 2/6 or 1/3.
Maybe 2 out Of 3 Chances Just Like Divorces :D
1/10 not likely
5 + 11 11 + 5 7 + 9 9 + 7 So 4 ways if you are allowed to throw each die only once. But the question did not state that assumption; so the additional ways are: Throw die #1 16 times and get 1 each time. Throw die #2 16 times and get 1 each time. Throw die # 1 13 times and get 1 13 times and 3 once. Throw die # 2 13 times and get 1 13 times and 3 once. Throw die #1 13 times and get 1 each time, then throw die # 2 once and get 3. Throw die #1 12 times and get 1 each time, then throw die #2 once and get 3, then throw die #1 again and get another 1. You get the idea, figure out the rest yourself.
A die has 6 sides and every side has the same probability of being chosen. So for any throw the possibility of getting a 2 is 1/6. If the die is thrown 100 times then the total number of all possible 2s would simply be (1/6)x100 or 16. To get a 2 on every throw becomes (1/6)100 or 1.5306467074865063414445284410446e-78
It is 3/8
2/25
Im not sure what your chances are but I can tell you from experience that no 2 pregnancys are alike.