Two independent outcomes with constant probabilities.
With 1000 rolls of a die, and each number having a probability of 1/6, I would not expect any peaks.
The probability of it snowing is an excellent question, usually answered with a statistic (incorrectly) by your local, friendly weatherman. Here's a quick guide to know when it will snow: IF: Your weatherman has said to expect several inches, expect a light dusting, possibly no-stick. IF: Your weatherman has said to expect nothing, prepare for a blizzard. IF: Your weatherman has said to expect sunshine, and clear skies, don't go on any parades, for fear of cliche. (Rain on parade)
the answer is the probability 6o =1/6 = 60%
the probability 6o =1/6 = 60%
Expected number of heads is 1/4 * 32 or 8 heads.
I expect you mean the probability mass function (pmf). Please see the right sidebar in the linked page.
With 1000 rolls of a die, and each number having a probability of 1/6, I would not expect any peaks.
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The answer will depend on how soon YOU expect it to arrive! If you think that it will take 5 minutes after you complete the transaction, the probability that it arrives earlier is 0 whereas if you expect it to take 5 moths, the probability that it arrives earlier is 1.The answer will depend on how soon YOU expect it to arrive! If you think that it will take 5 minutes after you complete the transaction, the probability that it arrives earlier is 0 whereas if you expect it to take 5 moths, the probability that it arrives earlier is 1.The answer will depend on how soon YOU expect it to arrive! If you think that it will take 5 minutes after you complete the transaction, the probability that it arrives earlier is 0 whereas if you expect it to take 5 moths, the probability that it arrives earlier is 1.The answer will depend on how soon YOU expect it to arrive! If you think that it will take 5 minutes after you complete the transaction, the probability that it arrives earlier is 0 whereas if you expect it to take 5 moths, the probability that it arrives earlier is 1.
It means there is a 5% chance of rain for the given day. If you were presented with 100 days of equivalent conditions, you would expect it to rain for 5 of them
What conditions did the British expect Zionists to meet?
Well, if you do a very specific operation, you wouldn't expect the result to be completely random.
To determine how many times Kareen should expect to win when spinning the arrow 10 times, we need to know the probability of winning on a single spin. If, for example, the probability of winning is 0.3 (or 30%), then he can expect to win about 3 times in 10 spins (10 spins × 0.3 probability = 3 wins). Adjust the expected number of wins based on the actual probability of winning in the game.
To get the EXPERIMENTAL probability, you'll have to actually carry out the experiment. The EXPECTED probability is equal to a fraction; the numerator will be the number of pieces of papers that have the number 35, the denominator will be the total number of pieces. If you repeat the experiment often, you can expect the experimental probability to be close to the expected probability.
The probability of rolling a 6 on a fair six-sided die is ( \frac{1}{6} ). For the compound event of rolling a 6 and getting heads on a coin, the probability is ( \frac{1}{6} \times \frac{1}{2} = \frac{1}{12} ). Since ( \frac{1}{6} ) is greater than ( \frac{1}{12} ), we would expect the probability of rolling a 6 to be greater than the probability of the compound event.
The probability of it snowing is an excellent question, usually answered with a statistic (incorrectly) by your local, friendly weatherman. Here's a quick guide to know when it will snow: IF: Your weatherman has said to expect several inches, expect a light dusting, possibly no-stick. IF: Your weatherman has said to expect nothing, prepare for a blizzard. IF: Your weatherman has said to expect sunshine, and clear skies, don't go on any parades, for fear of cliche. (Rain on parade)
the answer is the probability 6o =1/6 = 60%