1/6. With two dice there are 36 possible outcomes six of which are doubles 6/36= 1/6.
6 Of course - assuming a cube die. There are other dice available (for playing D&D) which can have for example 4 (tetrahedral dice) or 20 (icosahedral dice) outcomes.
There are 6 outcomes with one roll and 6^2 with two and 6^3 with three. So the answer is 216.
you will land on 1 or 6 5/6 times
1-(5/6)^60 ≈ 99.99822529882%
6
There are six possible outcomes. Assuming the probability of each outcome is the same (dice has no defects), then you are likely to roll the number two, 100/6=50/3=16.67 times.
69 lolz
6 outcomes each roll, 3 rolls. 6*6*6 = 216.
1/6. With two dice there are 36 possible outcomes six of which are doubles 6/36= 1/6.
6 Of course - assuming a cube die. There are other dice available (for playing D&D) which can have for example 4 (tetrahedral dice) or 20 (icosahedral dice) outcomes.
There is 6 possible outcomes per roll of a die. So, there are 6*6*6*6 outcomes or 64 or 1296 possible outcomes.
There are 6 outcomes with one roll and 6^2 with two and 6^3 with three. So the answer is 216.
you will land on 1 or 6 5/6 times
The probability of a sum of seven if you roll two dice is 6/36 or 1/6. There are 6 ways to roll a 7; (6,1) (5,2) (4,3) (3,4) (2,5) & (1,6) and 36 possible outcomes.
Possible outcomes of a single dice are 6 ( 1,2,3,4,5,6) So if 5 such dices are rolled then the number of possible outcomes are 6 mulitiplied by 6 five times. 6x6x6x6x6x6=46656 possible outcomes.
The sample space for 1 roll is of size 6.