1 sigma does not represent 68.8 percent of anything.The area under the standard normal curve, between -0.5 and +0.5, that i, the central 1 sigma, is equal to 0.68269 or 68.3%.
Yes. The total area under any probability distribution curve is always the probability of all possible outcomes - which is 1.
The area under the normal distribution curve represents the probability of an event occurring that is normally distributed. So, the area under the entire normal distribution curve must be 1 (equal to 100%). For example, if the mean (average) male height is 5'10" then there is a 50% chance that a randomly selected male will have a height that is below or exactly 5'10". This is because the area under the normal curve from the left hand side up to the mean consists of half of the entire area of the normal curve. This leads us to the definitions of z-scores and standard deviations to represent how far along the normal curve a particular value is. We can calculate the likelihood of the value by finding the area under the normal curve to that point, usually by using a z-score cdf (cumulative density function) utility of a calculator or statistics software.
the standard normal curve 2
A z-chart in statistics is a chart that contains the values that represent the areas under the standard normal curve for the values between 0 and the relative Z-score.
WORK
The area under a displacement over force graph represents work done. It indicates the amount of energy transferred when a force acts over a particular displacement.
To find the displacement from a negative velocity-time graph, you need to calculate the area under the curve for the portion representing displacement. If the velocity is negative, the displacement will be in the opposite direction. The magnitude of the displacement is equal to the absolute value of the area under the curve.
Displacement
The work done is equal to the area under the curve on a force versus displacement graph. To find the work, calculate the area of the shape(s) represented by the graph. This can be done by breaking down the shape into simpler geometrical shapes and calculating their areas.
The work done for a force that is applied gradually can be calculated by integrating the force with respect to displacement over the distance the force is applied. This involves finding the area under the force-displacement curve. The work done is equal to the change in energy of the object the force is acting upon.
On a graph showing the motion of an object, variables such as time (on the x-axis) and position or displacement (on the y-axis) would be used. The slope of the graph would represent the object's velocity, while the area under the curve would represent the object's displacement.
A force does no work when there is no displacement of the object it is acting on, or when the force is perpendicular to the direction of motion. Another condition is when the force applied is zero, since work is the product of force and displacement.
It is not, if it is a graph of force against acceleration.
The momentum-time graph is the integral of the force-time graph. that is, it is the area under the curve of the f-t graph.The momentum-time graph is the integral of the force-time graph. that is, it is the area under the curve of the f-t graph.The momentum-time graph is the integral of the force-time graph. that is, it is the area under the curve of the f-t graph.The momentum-time graph is the integral of the force-time graph. that is, it is the area under the curve of the f-t graph.
The area under a force-displacement graph represents the work done on an object. Work is defined as the force applied to an object multiplied by the distance the force is applied over.
There is no such thing as a "slope under the curve", so I assume that you mean "slope of the curve". If the curve is d vs. t, where d is displacement and t is time, then the slope at any given point will yield (reveal) the velocity, since velocity is defined as the rate of change of distance with respect to time. Mathematically speaking, velocity is the first derivative of position with respect to time. The second derivative - change in velocity with respect to time - is acceleration.