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Q: What does the sum of the deviations from the mean equal?
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What is the sum of the deviations from the mean?

The sum of standard deviations from the mean is the error.


The sum of the deviations about the mean always equals what?

The sum of total deviations about the mean is the total variance. * * * * * No it is not - that is the sum of their SQUARES. The sum of the deviations is always zero.


Is the sum of deviations from the mean equal to zero in symmetrical distributions?

It is equal to zero in ALL distributions.


What does the sum of the deviations of each value from the mean equal?

The sum will be zero or close to zero, depending on how the sampling was done. See related question.


In any distribution is the sum of the squared deviations from the mean always equal to zero?

No. It cannot be. Remember that when you square a negative number it becomes a positive number. Thus all squared deviations are positive and their sum must be positive.


The sum of the deviations from the mean is always?

0 (zero).


How do you calculate the sum of the deviations from the mean?

multiply the mean by the amount of numbers


The sum of deviations of the individual data elements from their mean is?

zero


For which measure of central tendency will the sum of the deviations always be zero?

Mean


The sum of the deviations from the mean is always zero?

The definition of the mean x of a set of data is the sum of all the values divided by the total number of observations, and this value is in turn subtracted from each x value to calculate the deviations. When the deviations from the average are added up, the sum will always be zero because of the negative signs in the sum of deviations. Going back to the definition of the mean, the equation provided (x = Σxi/n) can be manipulated to read Σxi - x = 0


What is the Sum of deviation from the mean is?

The sum of deviations from the mean, for any set of numbers, is always zero. For this reason it is quite useless.


What is the sum of the squared deviations from the mean divided by the count minus one?

variation