It is equal to zero in ALL distributions.
for symmetrical distributions your mean equals the median. that is one of the properties of the symmetrical distribution.
They do happen, particularly with very skewed distributions.
No, not all distributions are symmetrical, and not all distributions have a single peak.
Zero.
The median and mode.
for symmetrical distributions your mean equals the median. that is one of the properties of the symmetrical distribution.
True. Two normal distributions that have the same mean are centered at the same point on the horizontal axis, regardless of their standard deviations. The standard deviation affects the spread or width of the distributions, but it does not change their center location. Therefore, even with different standard deviations, the distributions will overlap at the mean.
No, not all distributions are symmetrical, and not all distributions have a single peak.
They do happen, particularly with very skewed distributions.
Zero.
The two distributions are symmetrical about the same point (the mean). The distribution where the sd is larger will be more flattened - with a lower peak and more spread out.
-It is symmetrical (mean = median) -It is bell shaped (empirical rule applies) -The interquartile range equals 1.33 standard deviations -The range is appr. equal to 6 stand. dev.
No. They are equal only if the distribution is symmetrical.
The mean, median, and mode are all measures of central tendency. For symmetrical distributions they all have the same value. For assymetrical distributions they have different values. The mean is the average and the mode is the most likely value.
Yes, and they WILL be if the distribution is symmetrical.
The median and mode.
The mean being equal to the range has nothing to do with symmetry.