There are 8 possible outcomes when a coin is tossed 3 times. Here they are:1. Heads, Heads, Tails.2. Heads, Tails, Heads.3. Tails, Heads, Heads.4. Heads, Heads, Heads.5. Tails, Tails, Heads.6. Tails, Heads, Tails.7. Heads, Tails, Tails.8. Tails, Tails, Tails.There is only one outcome that is heads, heads, heads, so the probability of three heads coming up in three coin tosses is 1 in 8 or 0.125 for that probability.
1heads heads heads 2heads heads tails 3heads tails heads 4heads tails tails 5tails tails tails 6tails tails heads 7tails heads tails 8tails heads heads
Your question is slightly vague, so I will pose a more defined question: What is the probability of 3 coin tosses resulting in heads exactly twice? This is a pretty easy question to answer. The three possible (winning) outcomes are: 1. Heads, Heads, Tails. 2. Heads, Tails, Heads. 3. Tails, Heads, Heads. If we look at the possible combination of other (losing) outcomes, we can easily determine the probability: 4. Heads, Heads, Heads. 5. Tails, Tails, Heads. 6. Tails, Heads, Tails. 7. Heads, Tails, Tails. 8. Tails, Tails, Tails. This means that to throw heads twice in 3 flips, we have a 3 in 8 chance. This is because there are 3 winning possibilities out of a total of 8 winning and losing possibilities.
If you roll a standard die and flip a penny at the same time, there are 12 possible outcomes. You can find this out quickly by multiplying the number of outcomes of the coin (2) by the number of outcomes of the die (6). Here they are: Heads, 1 Heads, 2 Heads, 3 Heads, 4 Heads, 5 Heads, 6 Tails, 1 Tails, 2 Tails, 3 Tails, 4 Tails, 5 Tails, 6
5
There are 8 possible outcomes when a coin is tossed 3 times. Here they are:1. Heads, Heads, Tails.2. Heads, Tails, Heads.3. Tails, Heads, Heads.4. Heads, Heads, Heads.5. Tails, Tails, Heads.6. Tails, Heads, Tails.7. Heads, Tails, Tails.8. Tails, Tails, Tails.There is only one outcome that is heads, heads, heads, so the probability of three heads coming up in three coin tosses is 1 in 8 or 0.125 for that probability.
1heads heads heads 2heads heads tails 3heads tails heads 4heads tails tails 5tails tails tails 6tails tails heads 7tails heads tails 8tails heads heads
When h=head, t=tails First toss: heads/tails (1h/1t) Second toss: heads/tails (2h/1h1t*2/2t) Third toss: heads/tails (3h/2h1t*3/1h2t*3/3t) Fourth toss: heads/tails (4h/3h1t*4/2h2t*6/1h3t*4/4t) In short, 1+4+6+4+1=16 Chances of getting 2 heads and 2 tails = 6/16 * 100% = 37.5%
Your question is slightly vague, so I will pose a more defined question: What is the probability of 3 coin tosses resulting in heads exactly twice? This is a pretty easy question to answer. The three possible (winning) outcomes are: 1. Heads, Heads, Tails. 2. Heads, Tails, Heads. 3. Tails, Heads, Heads. If we look at the possible combination of other (losing) outcomes, we can easily determine the probability: 4. Heads, Heads, Heads. 5. Tails, Tails, Heads. 6. Tails, Heads, Tails. 7. Heads, Tails, Tails. 8. Tails, Tails, Tails. This means that to throw heads twice in 3 flips, we have a 3 in 8 chance. This is because there are 3 winning possibilities out of a total of 8 winning and losing possibilities.
If you roll a standard die and flip a penny at the same time, there are 12 possible outcomes. You can find this out quickly by multiplying the number of outcomes of the coin (2) by the number of outcomes of the die (6). Here they are: Heads, 1 Heads, 2 Heads, 3 Heads, 4 Heads, 5 Heads, 6 Tails, 1 Tails, 2 Tails, 3 Tails, 4 Tails, 5 Tails, 6
The probability of 2 coins both landing on heads or both landing on tails is 1/2 because there are 4 possible outcomes. Head, head. Head, tails. Tails, tails. Tails, heads. Tails, heads is different from heads, tails for reasons I am unsure of.
Heads+Heads ; Heads+Tails ; Tails+Tails
2 heads and 2 tails
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Half the time they will be the same, half the time they will be different. Half of the time that they're the same they will be heads, half the time they are the same they will be tails. It's your homework, YOU figure it out. The way I figure it. There are four options: 1) heads / heads 2) heads / tails 3) tails / heads 4) tails / tails By process of chance, one out of four times both coins will be heads/heads. Therefore 780/4 = 195 times.
If 10 coins are tossed, you could get 4 heads and 6 tails, 3 heads and 7 tails, 2 heads and 1 tail, 0 heads and 10 tails all giving fewer heads than tails. Using the binomial distribution , P(4 heads) = 10C4 (.5)^4 (.5)^6 = 0.205078. P(3 heads) = 10C3 (.5)^3 (.5)^7 = 0.117188 P(2 heads) = 10C2 (.5)^2 (.5)^8 = 0.043945 P(1 heads) = 10C1 (.5)^1 (.5)^9 = 0.009766 P(0 heads) =(.5)^10 = 0.000977 Adding all of these probabilities, we have P(fewer heads than tails)= 0.376953
There are eight possible results when flipping three coins (eliminating the highly unlikely scenario of one or more coins landing on their edge): Dime - Heads / Nickel - Heads / Penny - Heads Dime - Heads / Nickel - Heads / Penny - Tails Dime - Heads / Nickel - Tails / Penny - Heads Dime - Heads / Nickel - Tails / Penny - Tails Dime - Tails / Nickel - Heads / Penny - Heads Dime - Tails / Nickel - Heads / Penny - Tails Dime - Tails / Nickel - Tails / Penny - Heads Dime - Tails / Nickel - Tails / Penny - Tails