An ogive is a cumulative relative frequency diagram. Interpolation is definiting the midpoint (50%) of this line
interpolation
Both, interpolation and extrapolation are used to predict, or estimate, the value of one variable when the value (or values) of other variable (or variables) is known. This is done by extending evaluating the underlying function. For interpolation, the point in question is within the domain of the observed values (there are observations for greater and for smaller values of the variables) wheres for extrapolation the point in question is outside the domain.
torque * newtons per period.
Re-arrange the data in increasing order.If there are n data points, calculate (n+1)/4.Find the data point in position (n+1)/4, using interpolation if required. This is the LOWER QUARTILE.Find the data point in position 3*(n+1)/4, using interpolation if required. This is the UPPER QUARTILE.In n is large (>30, say), don't bother to add 1: just work with the observations in the n/4th and 3n/4th positions.
when the value of x for which f(y) is to be found lies in the upper part of forward difference table then we use Newton's forward interpolation formula..
pu = p0 + u(p1 - p0)
Formula: pounds x 4.448 = newtons
Also if you mean Newtons in terms of weight the formula is Newtons = Mass * Gravity
The process is called interpolation, which applies a computed formula of the line to a given x or y value. (More specifically, it is "linear interpolation".)
Newton's forward interpolation formula is derived by constructing a series of finite divided differences based on the given data points, then expressing the interpolation polynomial using these differences. By determining the first divided difference as the increments of function values, and subsequent divided differences as the increments of the previous differences, the formula is formulated algebraically as a series of terms involving these differences. This results in a polynomial that can be used to interpolate values within the given data range using forward differences.
F = m a
P=newtons/area... Area is squared... newtons is the stationary form for force.
If by N you mean Newtons, then the formula to use would be Force=mass x acceleration. Newtons is the unit of measurement for force
There are 50.98 kilograms in 500 newtons, assuming standard gravity of 9.81 m/s^2. This conversion is based on the formula: 1 kilogram is equal to 9.81 newtons.
The interpolation factor is simply the ratio of the output rate to the input
The noun interpolation (determine by comparison) has a normal plural, interpolations.