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An ogive is a cumulative relative frequency diagram. Interpolation is definiting the midpoint (50%) of this line
interpolation
Both, interpolation and extrapolation are used to predict, or estimate, the value of one variable when the value (or values) of other variable (or variables) is known. This is done by extending evaluating the underlying function. For interpolation, the point in question is within the domain of the observed values (there are observations for greater and for smaller values of the variables) wheres for extrapolation the point in question is outside the domain.
torque * newtons per period.
Re-arrange the data in increasing order.If there are n data points, calculate (n+1)/4.Find the data point in position (n+1)/4, using interpolation if required. This is the LOWER QUARTILE.Find the data point in position 3*(n+1)/4, using interpolation if required. This is the UPPER QUARTILE.In n is large (>30, say), don't bother to add 1: just work with the observations in the n/4th and 3n/4th positions.
when the value of x for which f(y) is to be found lies in the upper part of forward difference table then we use Newton's forward interpolation formula..
pu = p0 + u(p1 - p0)
Formula: pounds x 4.448 = newtons
Also if you mean Newtons in terms of weight the formula is Newtons = Mass * Gravity
The process is called interpolation, which applies a computed formula of the line to a given x or y value. (More specifically, it is "linear interpolation".)
mass = Force ___________ This formula is from Newtons second law. acceleration
T= Ta + (Tb-Ta)((H-Ha)/(Hb-Ha))
F = m a
If by N you mean Newtons, then the formula to use would be Force=mass x acceleration. Newtons is the unit of measurement for force
P=newtons/area... Area is squared... newtons is the stationary form for force.
The noun interpolation (determine by comparison) has a normal plural, interpolations.
The interpolation factor is simply the ratio of the output rate to the input