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An ogive is a cumulative relative frequency diagram. Interpolation is definiting the midpoint (50%) of this line
interpolation
Both, interpolation and extrapolation are used to predict, or estimate, the value of one variable when the value (or values) of other variable (or variables) is known. This is done by extending evaluating the underlying function. For interpolation, the point in question is within the domain of the observed values (there are observations for greater and for smaller values of the variables) wheres for extrapolation the point in question is outside the domain.
torque * newtons per period.
Re-arrange the data in increasing order.If there are n data points, calculate (n+1)/4.Find the data point in position (n+1)/4, using interpolation if required. This is the LOWER QUARTILE.Find the data point in position 3*(n+1)/4, using interpolation if required. This is the UPPER QUARTILE.In n is large (>30, say), don't bother to add 1: just work with the observations in the n/4th and 3n/4th positions.
when the value of x for which f(y) is to be found lies in the upper part of forward difference table then we use Newton's forward interpolation formula..
pu = p0 + u(p1 - p0)
Newton's backward interpolation formula is used to estimate the value of a function at a point within a given range of discrete data points, particularly when the desired point is near the end of the dataset. It employs divided differences based on the values of the function at these data points, using the most recent points for interpolation. This technique is especially useful when dealing with equally spaced data, allowing for efficient computation of interpolated values. Common applications include numerical analysis, engineering, and computer graphics where precise function estimation is required.
Formula: pounds x 4.448 = newtons
Also if you mean Newtons in terms of weight the formula is Newtons = Mass * Gravity
The process is called interpolation, which applies a computed formula of the line to a given x or y value. (More specifically, it is "linear interpolation".)
The formula to calculate force in newtons is force mass x acceleration.
Newton's forward interpolation formula is derived by constructing a series of finite divided differences based on the given data points, then expressing the interpolation polynomial using these differences. By determining the first divided difference as the increments of function values, and subsequent divided differences as the increments of the previous differences, the formula is formulated algebraically as a series of terms involving these differences. This results in a polynomial that can be used to interpolate values within the given data range using forward differences.
F = m a
There are 50.98 kilograms in 500 newtons, assuming standard gravity of 9.81 m/s^2. This conversion is based on the formula: 1 kilogram is equal to 9.81 newtons.
P=newtons/area... Area is squared... newtons is the stationary form for force.
If by N you mean Newtons, then the formula to use would be Force=mass x acceleration. Newtons is the unit of measurement for force