We can write the sample space for 3 children as follows (b=boy, g=girl). bbb gbb bbg gbg bgb ggg bgg ggb The sample space is 8; each has a probability of 1/8. From above, you can see 3 instances that have 1 boy; bgg, gbg & ggb. Therefore, add 1/8 + 1/8 + 1/8 = 3/8 probability one boy having three children.
2/6 is not accurate. using a theoretical method for equally likely outcomes, there are 2 possible outcomes for each birth: either a boy(B), or a girl (G). For a family of three children, the total number of possibilities (birth orders) is 2*2*2=8 to double check this work, here are the eight possible outcomes:BBB, BBG, BGG, GBB, GBG, GGB, and GGG. You want EXACTLY two girls, this assumes that the other must be a boy. Therefore, the probability that a three child family has 2 girls one boy is P(2 girls)=3/8=0.375
As asked - this question has no calculable answer as it depends on the genetics of the parents but ...If we assume, to make the problem a little easier, that the odds of a boy are equal to the odds of a girl, then p(boy)=p(girl)=.5 Now, at least two boys means odd of 2 or 3 boys out of three children.The formula for finding k successes, (let's call a boy a success ONLY because that is what we are looking for) out of n trials (births) is P(n,k)=n!/(n-k)!k! (p)^k(q)^n-k ( note that the first part of this formula is 3Cn where n is 2 or 3 in this case.So P(2,3)=3x2x1/2x1(.5)^2(.5) =3(.25)(.5)=.375 and P(3,3)=3x2x1/3x2x1(.5)^3(.5)^0 =.125 Now add these two probabilities .375+.125=.5You could also just do a tree, with just the three children:B.G/ \B.G B.G/ . | . | . \B.G B.G B.G B.GThe first row is the first child, then if it's a boy, look to the left half. If the first one is a girl, look to the right half. So for 3 boys, follow the very left-hand path (B-B-B).There are 4 possibilities that yield 2 or more boys (out of the 8 total possibilities). These are {BBB, BBg, BgB, gBB}. I bolded the bottom-row ones that are the path to 2 or more boys. Probability = 4/8 = 0.5, or 50%. Doing this validates that the first method is correct (the graphical method becomes unwieldy when more events are added).One important rule to use in any problem that asks at least is the complement rule.The idea is simple. P(No boys )+ P( 1 boy) + P(2 boys) + P(3 boys)=1 since those are all the possible outcomes. We subtract P( No boys) and P(1 boy ) from both sides and we haveP(at least 2)=1-P(none)-P(1). In this case no boys means GGG and the chance of that is(1/2)^3 or 1/8. Also one Girl can be GBB, BGB or BBG and each has a 1/8 chance so the three together have a 3/8 chance. This means P( as least two boys)= 1-1/8-3/8 or 1-4/8=4/8 or 50%The "at least method is very useful when looking at large numbers of outcomes. For example, chance of at least 1 boy in 100 children. The tree would be hard to make and the binomial formula would take a long time to use. However 1-P(none) would give you the answer in a minute. It is 1-(1/2)^100.
BBG= Beautiful Baby Girl
"9 I in a BBG" is short for 9 innings in a baseball game.
Bill Barrett Corporation (BBG)had its IPO in 2004.
As of July 2014, the market cap for Bill Barrett Corporation (BBG) is $1,272,753,640.86.
omg bbg
Beautiful baby girl
Bbg
it usually means beautiful baby girl :)
3 Billy Goats Gruff
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post them to their facebook page they will reply if they have time
The airport code for Butaritari Atoll Airport is BBG.