We can write the sample space for 3 children as follows (b=boy, g=girl). bbb gbb bbg gbg bgb ggg bgg ggb The sample space is 8; each has a probability of 1/8. From above, you can see 3 instances that have 1 boy; bgg, gbg & ggb. Therefore, add 1/8 + 1/8 + 1/8 = 3/8 probability one boy having three children.
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Assuming the chances of having a boy and having a girl are equal (50/50), there are 4 possible outcomes from having 2 children. BOY-BOY, or GIRL-GIRL, or BOY-GIRL, or GIRL-BOY. Since each outcome is of equal probability it means there's a 25% chance the first will be a girl and the second will be a boy.
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes. However, if you assume that they are independent events then, given that the probability of a boy is approx 0.52, the probability of 3 girls out of 4 children is 0.2331
The probability of having a girl versus a boy is 1/2 because there is two things you have a chance of getting and you can only get one or the other.
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Assuming that the probability of having a baby girl is 1/2 and that of having a baby boy is 1/2, the probability of having 3 baby girls in a row is (1/2)(1/2)(1/2)=1/8.