4/16 or 0.2 or 25%
It is 3/8.
2/4
50-50
In a family with four children, the probability of having four boys is 1 in 16.
there is a 50% chance that two of them will be girls
It is 3/8.
6 out of 9.
To determine the probability of selecting a family with exactly 3 male children out of 4, we can use the binomial probability formula. The probability of having a male child is typically considered to be 0.5 (assuming an equal likelihood of male and female). The probability of exactly 3 males in 4 children is calculated as ( P(X = 3) = \binom{4}{3} (0.5)^3 (0.5)^1 = 4 \times 0.125 \times 0.5 = 0.25 ). Thus, the probability is 0.25 or 25%.
The probability of exactly 3 girls in a family of 10 children, assuming equal chance of a boy or girl, is 0.1172. This is a binomial distribution.
It is 3/8.
2/4
50-50
The probability is 2 - 6
In a family with four children, the probability of having four boys is 1 in 16.
Probability equals the number of ways an event can occur divided by the total number of events. The total number of events is (b=boy, g=girl) is bb, bg, gb, gg. The probability is then 1/4.
1 in 64
We would need to know the number of children in the family to answer this question. For instance, the probability of having no girls in a family of two children would be 1/4 theoretically. In general it is 2-n where n is the number of children.