The mean absolute deviation is 2
5.142857143 is the mean.12.43956044 is the variance.3.526976104 is the standard deviation.
A large standard deviation indicates that the distribution is heavily weighted far from the mean. Take the following example: {1,1,1,1,1,19,19,19,19,19} Mean is 10 and StDev = 9.49 Now look at this data set: {5, 6, 7, 8, 9, 11, 12, 13, 14, 15} Mean is still 10, but StDev = 3.5
For 8 9 9 9 10 11 11 12: σ=1.3562
7.087547766 is the standard deviation for those figures.
11
To calculate the mean absolute deviation (MAD), first, find the mean of the data set: (16 + 19 + 20 + 22 + 26 + 34 + 35 + 39) / 8 = 24. Next, calculate the absolute deviations from the mean: |16-24|, |19-24|, |20-24|, |22-24|, |26-24|, |34-24|, |35-24|, |39-24|, which results in 8, 5, 4, 2, 2, 10, 11, and 15. The average of these absolute deviations is (8 + 5 + 4 + 2 + 2 + 10 + 11 + 15) / 8 = 7.125. Thus, the mean absolute deviation is 7.125.
5.142857143 is the mean.12.43956044 is the variance.3.526976104 is the standard deviation.
A large standard deviation indicates that the distribution is heavily weighted far from the mean. Take the following example: {1,1,1,1,1,19,19,19,19,19} Mean is 10 and StDev = 9.49 Now look at this data set: {5, 6, 7, 8, 9, 11, 12, 13, 14, 15} Mean is still 10, but StDev = 3.5
For 8 9 9 9 10 11 11 12: σ=1.3562
If "standard" is meant to be standard deviation, the answer is the second.
Think of the absolute value of a number as it's distance from the origin or zero point on the number line. Since it is a distance it is always going to be positive. The absolute value of -11 is then 11.Absolute value of -11 is 11.
3.898717738 is the standard deviation.
(85 - 58)/11 = 27/11 = 2.4545.. sd
If you mean -3a = 10-11 then a = 1/3
If you mean: 8 9 10 11 and 12 then the average mean is 10
11
mean = 11ftstandard deviation = 1.6ftx=13z= 13-11 = 1.251.6P(0