To calculate the mean absolute deviation (MAD), first, find the mean of the data set: (16 + 19 + 20 + 22 + 26 + 34 + 35 + 39) / 8 = 24. Next, calculate the absolute deviations from the mean: |16-24|, |19-24|, |20-24|, |22-24|, |26-24|, |34-24|, |35-24|, |39-24|, which results in 8, 5, 4, 2, 2, 10, 11, and 15. The average of these absolute deviations is (8 + 5 + 4 + 2 + 2 + 10 + 11 + 15) / 8 = 7.125. Thus, the mean absolute deviation is 7.125.
That depends on what the standard deviation is.
To analyze the hypothetical population with ages 13, 16, 19, 23, 24, 27, 29, and 30, we can calculate the mean and standard deviation. The mean age is calculated as the sum of all ages divided by the number of individuals, which gives a mean of 23.125 years. The standard deviation, which measures the dispersion of ages around the mean, is approximately 5.139 years.
Mean μ = 63.3 Standard deviation σ = 3.82 Standard error σ / √ n = 3.82 / √ 19 = 0.8763681 z = (xbar - μ) / (σ / √ n ) z = (61.6-63.3) / 0.876368 z = -1.9398
absolute means the value without the sign: |x| = x if x ≥ 0 |x| = -x if x < 0 →|-13| = 13 →|19| = 19 19 > 13 → |19| > |-13|
15.5
19
That depends on what the standard deviation is.
To analyze the hypothetical population with ages 13, 16, 19, 23, 24, 27, 29, and 30, we can calculate the mean and standard deviation. The mean age is calculated as the sum of all ages divided by the number of individuals, which gives a mean of 23.125 years. The standard deviation, which measures the dispersion of ages around the mean, is approximately 5.139 years.
The absolute value of 19 is 19. If x is positive , absolute x equals x.
19
Mean μ = 63.3 Standard deviation σ = 3.82 Standard error σ / √ n = 3.82 / √ 19 = 0.8763681 z = (xbar - μ) / (σ / √ n ) z = (61.6-63.3) / 0.876368 z = -1.9398
absolute means the value without the sign: |x| = x if x ≥ 0 |x| = -x if x < 0 →|-13| = 13 →|19| = 19 19 > 13 → |19| > |-13|
20.37 is the mean.
19
15.5
The range is 12 and the standard deviation is 3.822448314.
7.087547766 is the standard deviation for those figures.