For the set (87 81 75 75 75 70 62 62 62 62 62 56 56): The mean is 68.076923 repeating The median is 62 The mode is 62
There are an infinite list of different sets of 5 that do that.If their mean is 80, then the only thing you know about them is that they add up to 400.Here's one set:78, 79, 80, 81, 82Here's another one:79, 81, -600, 400, 440.The mean doesn't tell us anything about what the individual numbers must be.
The median of these fourteen numbers is 84.
√16 x √81 = 4 x 9 = 36
59 of them. Any 2-digit number, from 41 to 99 (inclusive), rounded to the nearest 80 would lead to 80.A:It depends on what you are rounding to. Assuming you are rounding to the nearest tens it would be the following:75, 76, 77, 78, 79, 80, 81, 82, 83, & 84
The median and mode are both 82. The mean is 84.6
(79, 81, 82, 91, 93, 95, 95) The mean is 88 The mode is 95 The median is 91
It is 80.5, the number halfway between them. Median means "half of the numbers are above and half are below". With only two numbers we just split the difference. In this case the Median and the Mean are the same number - but this is not always the case. If our numbers were 80, 80, 81, 83, the Median would still be 80.5 but the Mean would be 81.
Mean: 69 Median: 67 Mode: 83, 61
Assuming you mean the arithmetic mean, it is 80.
For the set (87 81 75 75 75 70 62 62 62 62 62 56 56): The mean is 68.076923 repeating The median is 62 The mode is 62
median is 79. Write in order; median is middle number: {72, 89, 67, 81, 75, 79, 81, 80, 62, 64, 83} → {62, 64, 67, 72, 75, 79, 80, 81, 81, 83, 89} To find middle number, count the number of data items, add 1 and divide by 2. If this is a whole number, that is the data item which is the median; if it is a fraction, take the mean average of the data items of the positions either side of the fraction (eg if the fraction is 3.5, take the mean average of the 3rd and 4th data items) There are 11 data items → median is (11+1)/2 = 6th data item → median is 79
For median the list needs to be sorted into increasing order, but doing so also helps with the range and mode, so I'll do that first: {89, 76, 85, 76, 77, 84} → {76, 76, 77, 84, 85, 89} Mean: add them up and divide the sum by how many numbers there are: mean = (89 + 76 + 85 + 76 + 77 + 84) / 6 = 81 1/6 ≈ 81.167 Median: middle number when listed in order; if there are an even number of data items, then the median is the mean average of the middle two: There are 6 data items so median is mean average of middle two: median = (77 + 84) / 2 = 80 ½ = 80.5 Mode: the most frequent, it the number which occurs the most often. There can be more than one mode: mode = 76 as there are two of them and only 1 of all the other numbers. Range: the difference between the greatest and least numbers: range = 89 - 76 = 13
I'm going to guess that's the set (5, 5, 6, 7, 8, 8, 10, 10, 10, 12) Sum: 81 Mean: 8.1 Mode: 10 Range: 7
The median is 87.
It depends on what average you want to find. To find the mean of 81, 81, 98, and 91 add the numbers together and divide by 4 (the number of numbers you added). 81 + 81 + 98 + 91 = 351 351 divided by 4 = 87.75. To find the median, list the numbers in order and find the one in the middle. 81, 81, 91, 98 81 and 91 are in the middle. To find the mode, look for the number that appears the most, 81 appears twice and the other numbers appear once. 81 is the mode.
Mean is adding all of the numbers total and dividing by how many numbers there are. Mean is the middle number. Example: (Image 1) Not all the time do the numbers line up, For Example: 70, 75, 79, 80, 81, 82, 87, 91, 96, 96 Mean: 837รท10=83.7 Median:81.5 Mode:96