90, 91,92,93,94,95,96,97,98,99,100.
There are eleven terms. To find the median, you take the absolute middle term.
The absolute middle term is '95'.
NB You will notice that there are five terms to the left of 95, and five terms to the right of 95.
The median is (89 + 91)/2 = 90
85 91 48 98 99 91 90 84 91 To find the median, first rearrange the numbers in rank order. That is from lowest to highest. Hence 48,84,85,90,91,91,91,98,99. Next we notice that there are nine terms. To find the median we than take the absolute middle term. In this case it is '91'. There are four terms to the left and right of the median term. NB If you had left the numbers in the original order, the median would have been '99', which is incorrect. NNB As an aside the MODE is also '91'. However, in this case it is found by looking for the term that occurs most frequently. In this case there are three lots of '91' , but only one of each other term. Hope that helps !!!!
The first step in constructing a box-and-whisker plot is to first find the median, thelower quartile and the upper quartile of a given set of data. Example: The following set of numbers are the amount of marbles fifteen different boys own (they are arranged from least to greatest).18 27 34 52 54 59 61 68 78 82 85 87 91 93 100First find the median. The median is the value exactly in the middle of an ordered set of numbers. *68 is the medianNext, we consider only the values to the left of the median: 18 27 34 52 54 59 61. We now find the median of this set of numbers. Remember, the median is the value exactly in the middle oa an ordered set of numbers. Thus 52 is the median of the scores less than the median of all scores, and therefore is the lower quartile.52 is the lower quartileNow consider only the values to the right of the median: 78 82 85 87 91 93 100. We now find the median of this set of numbers. The median 87 is therefore called the upper quartile.87 is the upper quartile(*If you're finding the median in an ordered set with an even number of values, you must take the average of the two middle numbers. For example: 3, 5, 7, and 10. Add the two middle numbers. 5 + 7 = 12. Divided 12 by 2 to get the average. 12 / 2 = 6. Therefore 6 is the median for the ordered set of 3, 5, 7, and 10.)You are now ready to find the interquartile range (IQR).The interquartile range is the difference between the upper quartile and the lower quartile. In our case the IQR = 87 - 52 = 35. The IQR is a very useful measurement. It is useful because it is less influenced by extreme values, it limits the range to the middle 50% of the values.35 is the interquartile rangehere is a sucessful site called Jen's Box and Whisker plot, and here is a example of a whisker plot from that very own site. because itso hard to describe! i hope you find this helpful good luck!!
A 75 B 2 C 44 D 27 E 8 F 91 G 18 H 46 I 38 J 62? First put the numbers/terms in rank order. That is lowest to highest, or vice versa. 2,8,18,27,38,44,46,62,75,91. The MEDIAN is the absolute middle middle number. Since there are an even number of terms, there is no absolute middle term. So we take the two nearest to middle terms, they are 38 & 44. (NB This leaves four terms to the left of 38, and four terms to the right of 44. We then add the two terms and divide by '2'. Hence ( 38 + 44) / 2 = 82/2 = 41 '41' is the median.
There are three terms. You add the terms and divide by the numbers of terms to find the average/mean. Hence (91 + 93 + 95 ) / 3 279/ 3 = 93 the mean!!!!!
The median of those numbers is 90.
The median is (89 + 91)/2 = 90
Place the values in ascending order: 76, 81, 89, 91, 97, 99. There are 2 middle numbers; 89 & 91. The median is the mean of the 2 middle numbers; or (89+91)/2 or 90.
The mean is 92.7, if I am not mistaken (the sum of the 10 numbers divided by 10). The median is 91.5 (halfway between 91 and 92, the two numbers in the middle). The mode is 90, the only number that occurs twice.
91, 97.
There are 10 composite numbers from 90 to 100 (including the boundaries):90, 91, 92, 93, 94, 95, 96, 98, 99 and 100
The numbers 90, 91, 92, 93, 94, 95, 96, 98, 99 and 100 are composite (including the boundaries).
85 91 48 98 99 91 90 84 91 To find the median, first rearrange the numbers in rank order. That is from lowest to highest. Hence 48,84,85,90,91,91,91,98,99. Next we notice that there are nine terms. To find the median we than take the absolute middle term. In this case it is '91'. There are four terms to the left and right of the median term. NB If you had left the numbers in the original order, the median would have been '99', which is incorrect. NNB As an aside the MODE is also '91'. However, in this case it is found by looking for the term that occurs most frequently. In this case there are three lots of '91' , but only one of each other term. Hope that helps !!!!
91.
91 93 97
86
They are: 90 91 92 93 94 95 and 96 which are between the prime numbers of 89 and 97