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The next number has to be 41; you always add the powers of three to the previous number beginning with 0. 3^0=1; 1+1=2; 3^1=3; 2+3=5; 3^2=9; 5+9=14; 3^3=27; 14+27=41 the next number would be 122 (81+41); you could also multiply the number by 3 and then substract 1. By the way: x(n)=x(n-1)+3^(x-2) ------------------------------------------------------------------------------------------------------------------- It could also be the Catalan number sequence, found by 1/(n+1) * (2n choose n), in which case the next number would be 42.
560/14 = 40
14 lbs is greater
14 thousand = 0.014 million
5 ÷ 14 × 100 = 35.71%
It is 4n+2 and so the next number is 18
The nth term is: 3n+2 and so the next number will be 20
The given sequence appears to have a common difference of 3. Thus, the next term in the sequence would be 17.
14 20.02.18.04.16.06.14.08.12.10.10.12.08.14.06.16.04.18.02.20
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The given sequence (7, 14, 21, 28, 35,....) is an arithmetic sequence where each term increases by 7. The nth term of the given sequence is 7n
This appears to be a declining arithmetic series. If it is, the next term is 5, because each term is 3 less than the preceding term.=================================The 'N'th term is: [ 23 - 3N ].
14
14
14
14
18