the (n-1)th term plus the (n-2)th term.
Let n (i) = the term number of each term in the sequence., with (i) going from 1-6 E.g term number 1 (n (1) ) is 3. n(2)= -7 etc... Therefore n(i) for odd terms in the sequence is n (i)= (n (i -2)th term +1). For even terms in the sequence, n(i)= (n (i - 2)th term -3).
2,1,0 is th sequence of its terms
Use the following formula: an = a1 + (n - 1)d, where a1 = the first term n = the n th term (general term) d = common difference (which is constant between terms) Since we need to find the 14 th term, we can write: a1 = 100 n = 14 d = -4 an = a1 + (n - 1)d a14 = 100 + (14 - 1)(-4) a14 = 100 + (13)(-4) a14 = 100 - 52 a14 = 48 Thus, the 14 th term is 48.
This is the Fibonacci sequence, where the number is the sum of the two preceding numbers. The nth term is the (n-1)th term added to (n-2)th term
The answer depends on what the explicit rule is!
the (n-1)th term plus the (n-2)th term.
-13
Let n (i) = the term number of each term in the sequence., with (i) going from 1-6 E.g term number 1 (n (1) ) is 3. n(2)= -7 etc... Therefore n(i) for odd terms in the sequence is n (i)= (n (i -2)th term +1). For even terms in the sequence, n(i)= (n (i - 2)th term -3).
2,1,0 is th sequence of its terms
Use the following formula: an = a1 + (n - 1)d, where a1 = the first term n = the n th term (general term) d = common difference (which is constant between terms) Since we need to find the 14 th term, we can write: a1 = 100 n = 14 d = -4 an = a1 + (n - 1)d a14 = 100 + (14 - 1)(-4) a14 = 100 + (13)(-4) a14 = 100 - 52 a14 = 48 Thus, the 14 th term is 48.
This is the Fibonacci sequence, where the number is the sum of the two preceding numbers. The nth term is the (n-1)th term added to (n-2)th term
It is 5n+2 and so the next number is 22
The counting sequence is making increments of 11,that is, the n-th term will = 11 x nn = 12,t = 12 x 11= 132
10 - 52 = -15
Each number is twice the previous number.
How is th folowing least like the other glass, water, ice, snow