1/6
There are 36 possible outcomes.
If a normal die is rolled once, the outcomes are {1, 2, 3, 4, 5, 6}.
Possible Outcomes when die is rolleddot showed by die , possible outcome in single roll1,12,13,14,15,16,1thus , formula for the probability distribution of the random variable x will beP(X=x) = x/6Cx Where as x = 1
Each outcome is equally likely and so the probability of each outcome is 1/36.
It is an ordered pair of the form (A, n) where A is the outcome of the tossed coin (H or T) and n is the outcome of the rolled die (1, 2, 3, 4, 5, 6).
There are 36 possible outcomes.
If a normal die is rolled once, the outcomes are {1, 2, 3, 4, 5, 6}.
Possible Outcomes when die is rolleddot showed by die , possible outcome in single roll1,12,13,14,15,16,1thus , formula for the probability distribution of the random variable x will beP(X=x) = x/6Cx Where as x = 1
Each outcome is equally likely and so the probability of each outcome is 1/36.
It is an ordered pair of the form (A, n) where A is the outcome of the tossed coin (H or T) and n is the outcome of the rolled die (1, 2, 3, 4, 5, 6).
The outcome space.
Yes, it is possible.
It is 1/36 since each outcome is equally likely.
There are 6 outcomes when a die is rolled; 2 is one outcome so the probability of rolling a 2 is 1/6.
assuming the die is 1-6 there are six possible out comes. 1,2,3,4,5, and 6.
24 possible outcomes.
If 2 standard dice are rolled, the odds of getting a sum of 16 is zero. The highest sum possible is 12.