There are 36 possible outcomes.
Possible Outcomes when die is rolleddot showed by die , possible outcome in single roll1,12,13,14,15,16,1thus , formula for the probability distribution of the random variable x will beP(X=x) = x/6Cx Where as x = 1
If a normal die is rolled once, the outcomes are {1, 2, 3, 4, 5, 6}.
Each outcome is equally likely and so the probability of each outcome is 1/36.
It is an ordered pair of the form (A, n) where A is the outcome of the tossed coin (H or T) and n is the outcome of the rolled die (1, 2, 3, 4, 5, 6).
There are 36 possible outcomes.
Possible Outcomes when die is rolleddot showed by die , possible outcome in single roll1,12,13,14,15,16,1thus , formula for the probability distribution of the random variable x will beP(X=x) = x/6Cx Where as x = 1
If a normal die is rolled once, the outcomes are {1, 2, 3, 4, 5, 6}.
Each outcome is equally likely and so the probability of each outcome is 1/36.
It is an ordered pair of the form (A, n) where A is the outcome of the tossed coin (H or T) and n is the outcome of the rolled die (1, 2, 3, 4, 5, 6).
The outcome space.
It is 1/36 since each outcome is equally likely.
Yes, it is possible.
There are 6 outcomes when a die is rolled; 2 is one outcome so the probability of rolling a 2 is 1/6.
assuming the die is 1-6 there are six possible out comes. 1,2,3,4,5, and 6.
24 possible outcomes.
One die, two dice and no such word as dices! To chart the possible outcomes consider the set of ordered pairs (X, Y) where X is the outcome for the first die and Y is the outcome for the second die.