The is a binomial probability problem, The chance of heads=chance of tails=.5 The general formula for binomial probability is nCrxp^rq^n-r where p is a success and r is a failure. In this case it is 3C3x.5^3 which is 1x.125 so the answer is .125 Another way to think of this problem is the chance of heads is .5 on one toss. If we throw the coin again, the chance of heads is still .5 since this is an independent even and similarly for the third time. So the chance of 3 heads is .5x.5x.5=.125. A more concrete way to see this is List all possible outcomes in the sample space. This time consuming for large n, but for 3 we can do it. HHH, HTH, HHT, THH, HTT, THT, TTH, TTT so there are 8 or 2^3 possible outcomes. Only one of those is 3 heads so 1/8=.125
10 :)
The probability is 6 in 12, or 1 in 2.
What is the chance of it landing on heads twice in a row?
It is 5/32 = 0.15625
0.5, 1/2, 50% The probability for heads versus tails does not change based on the amount of times the coin is tossed. It will always be a 50% chance.
0
2:3...
The probability is 0.09766%.Each toss has a ½ chance to be heads. To combine probabilities use multiply them. So the probability to get two heads out of two tosses is ½ * ½, and three heads out of three tosses is ½ * ½ * ½. So the exact answer is 0.5^10
It is 3/4
10 :)
1/2
The probability is 6 in 12, or 1 in 2.
What is the chance of it landing on heads twice in a row?
The odds are 50/50. A tossed coin does not have a memory.
1/36
It is 5/32 = 0.15625
0.5, 1/2, 50% The probability for heads versus tails does not change based on the amount of times the coin is tossed. It will always be a 50% chance.