The question is ambiguous. It is in complete.
How many license plates can be made using either two uppercase English letters followed by four digits or two digits followed by four uppercase English letters?
35,152,000 (assuming that 000 is a valid number, and that no letter combinations are disallowed for offensive connotations.) Also, no letters are disallowed because of possible confusion between letters and numbers eg 0 and O.
it 26 to the power 4 and then 99 for the numbers figure that out add the two together
It is possible to create a 3-digit number, without repeated digits so the probability is 1.
2600
How many license plates can be made using either two uppercase English letters followed by four digits or two digits followed by four uppercase English letters?
There are up to 3 numbers and up to 5 letters in a UK postcode. One or two letters, followed by one or two digits OR one digit and a letter, followed by a space, followed by one digit, followed by two letters.
35,152,000 (assuming that 000 is a valid number, and that no letter combinations are disallowed for offensive connotations.) Also, no letters are disallowed because of possible confusion between letters and numbers eg 0 and O.
3!*3!=36For example, if you want to use the alphabets a,b,c and three digits 1,2,3 you can make the following 36 different passwords (3 letters followed by 3 digits)abc123abc132abc231abc213abc312abc321acb123acb132acb231acb213acb312acb321bca123bca132bca231bca213bca312bca321bac123bac132bac231bac213bac312bac321cab123cab132cab231cab213cab312cab321cba123cba132cab231cab213cab312cab321
Independent events, so P(both)=(5/26)(4/10)=0.07692307692. The 4/10 comes from the fact that 0, 3, 6, and 9 are the 4 digits that are multiples of 3.
None of the digits can be 10, so the probability is 0.
(26) x (26) x (10,000) = 6,760,000
There are 26 different letters that can be chosen for each letter. There are 10 different numbers that can be chosen for each number. Since each of the numbers/digits that can be chosen for each of the six "spots" are independent events, we can multiply these combinations using the multiplicative rule of probability.combinations = (# of different digits) * (# of different digits) * (# of different digits) * (# of different letters) * (# of different letters) * (# of different letters) = 10 * 10 * 10 * 26 * 26 * 26 = 103 * 263 = 1000 * 17576 = 17,576,000 different combinations.
If all letters and numbers are allowed, the possibilities are 26x26x10x10x10x10. So: 6760000 different plates.
It was digits followed by zero
A Pakistani passport number typically consists of 9 digits. The first two letters are followed by 7 digits. These digits are unique to each passport holder and are used for identification and verification purposes.
it 26 to the power 4 and then 99 for the numbers figure that out add the two together