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How many license plates can be made using either two uppercase English letters followed by four digits or two digits followed by four uppercase English letters?
How many license plates can be made using either two uppercase English letters followed by four digits or two digits followed by four uppercase English letters?
How many license plates can be made using either three digits followed by three letters or three letters followed by three digits?
35,152,000 (assuming that 000 is a valid number, and that no letter combinations are disallowed for offensive connotations.) Also, no letters are disallowed because of possible confusion between letters and numbers eg 0 and O.
How many license plates are possible if four letters are to be followed by two digits?
it 26 to the power 4 and then 99 for the numbers figure that out add the two together
What is the probability of three digit numbers without repeated digits with numbers 0123456?
It is possible to create a 3-digit number, without repeated digits so the probability is 1.
A License plate has 3 letters and 3 digits in that order A witness to a hit and run accident saw the first 2 two letters and last one digit If the digits and letters can be repeated?
2600
How many license plates can be made using either two uppercase English letters followed by four digits or two digits followed by four uppercase English letters?
How many license plates can be made using either two uppercase English letters followed by four digits or two digits followed by four uppercase English letters?
How many numbers has a postcode?
There are up to 3 numbers and up to 5 letters in a UK postcode. One or two letters, followed by one or two digits OR one digit and a letter, followed by a space, followed by one digit, followed by two letters.
How many license plates can be made using either three digits followed by three letters or three letters followed by three digits?
35,152,000 (assuming that 000 is a valid number, and that no letter combinations are disallowed for offensive connotations.) Also, no letters are disallowed because of possible confusion between letters and numbers eg 0 and O.
How many passwords can be made from 3 letters followed by 3 digits if no letter or digit can be used more than once?
3!*3!=36For example, if you want to use the alphabets a,b,c and three digits 1,2,3 you can make the following 36 different passwords (3 letters followed by 3 digits)abc123abc132abc231abc213abc312abc321acb123acb132acb231acb213acb312acb321bca123bca132bca231bca213bca312bca321bac123bac132bac231bac213bac312bac321cab123cab132cab231cab213cab312cab321cba123cba132cab231cab213cab312cab321
What A license plate consists of 2 letters followed by 4 digits letters and digits can be repeated. Find the probability that your new license plate begins with a vowel and ends with a multiple of 3.?
Independent events, so P(both)=(5/26)(4/10)=0.07692307692. The 4/10 comes from the fact that 0, 3, 6, and 9 are the 4 digits that are multiples of 3.
If two dice are thrown what is the probability that some of digits is ten?
None of the digits can be 10, so the probability is 0.
How many license plates are possible if two letters are to be followed by four digits?
(26) x (26) x (10,000) = 6,760,000
How many license plate combinations from 3 digits followed by 3 letters?
There are 26 different letters that can be chosen for each letter. There are 10 different numbers that can be chosen for each number. Since each of the numbers/digits that can be chosen for each of the six "spots" are independent events, we can multiply these combinations using the multiplicative rule of probability.combinations = (# of different digits) * (# of different digits) * (# of different digits) * (# of different letters) * (# of different letters) * (# of different letters) = 10 * 10 * 10 * 26 * 26 * 26 = 103 * 263 = 1000 * 17576 = 17,576,000 different combinations.
If a license plate consists of two letters followed by four digits how many different plates are possible?
If all letters and numbers are allowed, the possibilities are 26x26x10x10x10x10. So: 6760000 different plates.
What was first invented zero or digits?
It was digits followed by zero
How many digits are in Pakistani passport number?
A Pakistani passport number typically consists of 9 digits. The first two letters are followed by 7 digits. These digits are unique to each passport holder and are used for identification and verification purposes.
What is the probability of getting a license plate that has a repeated letter or digit if you live in a state that has two numerals followed by two letters followed by four numerals?
There are ten digits and twenty-six letters, assuming unconstrained choice of both. The probability of getting a repetition in the first two digits is 10/100, since there are 10 repetitious combinations of two digits among the 100 pairs of digits possible.To calculate the probability of a repetition in the two letters, consider that there are 262 combinations, of which 26 X 25 do not contain repetitions. (There is free choice among 26 alternatives for the first letter, but only 25 choice for the following letter.) Therefore, the probability of a repetition within the two letters is (26)(25)/262 or 25/26.The chance of a repeated digit within the four digit bloc is (10)(9)(8)(7)/104) or 504/1000.If there is no repetition of a digit within either the two-digit bloc or the four-digit bloc, there is still a chance of repetition of a digit between the blocs. The chance of this is (8 X 7 X 6 x 5)/104 or 168/1000.To reach the final answer, it is advantageous to calculate first the probability of not getting the specified repetition and then subtract this number from one. The probability of not getting a repetition in the first bloc is 9/10, and the probability of not getting a repetition between the first and second blocs is 168/1000. Therefore, the probability of not getting a repetition within the first bloc or between the first and the second number blocs is the product of these two, or 1512/10,000. Further multiplications by the independent probabilities of no repetition within the two remaining blocs yields a value of about 2.88 X 10-4. Therefore, the probability of at least one of the repetitions specified is about 0.999712.
