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What is the probability of drawing 2 hearts and then a spade in that order from a deck of 52 cards?
Wiki User
∙ 14y ago
In order to determine the probability of drawing 2 hearts and then a spade, in that order, from a deck of 52 cards, start by considering the first card.
The probability of drawing a heart is 1 in 4.
Since you have now reduced the number of hearts and the number of cards in the deck by one, the probability of drawing another heart is 4 in 17.
Since you have further reduced the number of cards by one, the probability of drawing a spade is 13 in 50.
Multiply these probabilities together, (1/4) (4/17) (13/50), and you get about 0.0153, or about 153 in 10000.
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∙ 14y ago
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What is the probability of drawing the jack of hearts then the queen of hearts?
It depends on what exactly the conditions are. If you mean from a 52 card deck, drawing one card right after the other, then the chance that they will be those two cards in that exact order is 1/52 * 1/51. This is pretty much a percent of a percent. .00038, or about 4 percent of a percent.
What is the probability of drawing 1 card from each suit if 4 cards are drawn from a deck?
The easiest way to do this is to first calculate the probability of drawing spade/heart/club/diamond in order. This is 13/52 times 13/51 time 13/50 times 13/49. Note that each time there are 13 possible cards to choose from out of a shrinking deck. This probability comes out at 0.004396. The reason it's so small is that we haven't accounted for all the different ways you can draw the cards. You might draw the spades first, or the hearts first. There are 4x3x2x1 different orders the cards can come in. Multiply the probability by this and you get 0.1055 So the probability of having 1 card from each suit is 0.1055
What is the probability of drawing an ace of spades and a heart from a deck of cards in two successive draws without placing the first card back in the deck of 52?
There's only one Ace of spades in a 52 card deck so it's 1/52 times the probability of drawing a heart (there are 13 hearts in the same deck, but now there are 51 cards because we already drew one out). That makes it 1/52 * 13/51 = 13/2652 = 1/204 This is if you want the Ace first, then the heart, if order doesn't matter, you add this to the probability of drawing the heart first, then the Ace of Spades which is (13/52*1/51) =1/204 notice is the same as the first one. So if order doesn't matter, the probability is 1/204 + 1/204 = 2/204 = 1/102
What is the probability of drawing a jack and a king?
The probability of drawing a jack and a king in that order from a standard deck is: P(J,K) = (4/52)∙(4/51) = 0.006033... ~ 0.006 ~ 0.6% The probability of drawing a jack and a king in any order is twice the above: P((J,K) or (K,J)) = 0.0112066... ~ 0.011 ~ 1.1%
What is the probability of drawing a spade and a diamond in any order?
Assume that you start with a well-shuffled regular 52-card deck (no jokers) and draw 2 cards. The first card can be either a spade or a diamond, giving you 26 possibilities out of the 52 cards, for a probability of 26/52 or 1/2. The second card must be of the other desired suit, giving you 13 possibilities out of the 51 remaining cards, for a probability of 13/51. The total probability is then the product of the two, 1/2 x 13/51 = 13/102, or about 12.74%.
What is the probability of drawing the jack of hearts then the queen of hearts?
It depends on what exactly the conditions are. If you mean from a 52 card deck, drawing one card right after the other, then the chance that they will be those two cards in that exact order is 1/52 * 1/51. This is pretty much a percent of a percent. .00038, or about 4 percent of a percent.
What is the probability of drawing 1 card from each suit if 4 cards are drawn from a deck?
The easiest way to do this is to first calculate the probability of drawing spade/heart/club/diamond in order. This is 13/52 times 13/51 time 13/50 times 13/49. Note that each time there are 13 possible cards to choose from out of a shrinking deck. This probability comes out at 0.004396. The reason it's so small is that we haven't accounted for all the different ways you can draw the cards. You might draw the spades first, or the hearts first. There are 4x3x2x1 different orders the cards can come in. Multiply the probability by this and you get 0.1055 So the probability of having 1 card from each suit is 0.1055
Two cards are drawn at random form a starnard deck of 52 cards without replacement what is the propertility of drawing a 7 and a king in that order?
You mean the PROBABILITY? It's 13/52*13/51 = 13/204
What is the probability of drawing an ace of spades and a heart from a deck of cards in two successive draws without placing the first card back in the deck of 52?
There's only one Ace of spades in a 52 card deck so it's 1/52 times the probability of drawing a heart (there are 13 hearts in the same deck, but now there are 51 cards because we already drew one out). That makes it 1/52 * 13/51 = 13/2652 = 1/204 This is if you want the Ace first, then the heart, if order doesn't matter, you add this to the probability of drawing the heart first, then the Ace of Spades which is (13/52*1/51) =1/204 notice is the same as the first one. So if order doesn't matter, the probability is 1/204 + 1/204 = 2/204 = 1/102
How do you calculate propability of a deck of cards?
The probability is the likely outcome of a random event. In this example - picking (say) the Ace of Spades - the chances are 1 in 52. Drawing a red card is 1 in 2, drawing a Spade is 1 in 13 etc. The probability of drawing every card in order from a pre-written list is approximately 1 in 8 x 1067 !
What is the probability of drawing a jack and a king?
The probability of drawing a jack and a king in that order from a standard deck is: P(J,K) = (4/52)∙(4/51) = 0.006033... ~ 0.006 ~ 0.6% The probability of drawing a jack and a king in any order is twice the above: P((J,K) or (K,J)) = 0.0112066... ~ 0.011 ~ 1.1%
If you draw a card from a standard deck of cards what is the probability of drawing a ace and a jack?
The probability of drawing an ace from a standard deck of cards.There are 52 cards in the deck (after discarding Jokers) and there are 4 aces.So: 4 out of 52 makes the probability 1 in 13 (one in thirteen).
What is the probability of the next card is higher if the card is 7 in 13 cards in an order?
It is 1/2 and depends on whether the cards are in ascending or descending order.
What is the probability of drawing a spade and a diamond in any order?
Assume that you start with a well-shuffled regular 52-card deck (no jokers) and draw 2 cards. The first card can be either a spade or a diamond, giving you 26 possibilities out of the 52 cards, for a probability of 26/52 or 1/2. The second card must be of the other desired suit, giving you 13 possibilities out of the 51 remaining cards, for a probability of 13/51. The total probability is then the product of the two, 1/2 x 13/51 = 13/102, or about 12.74%.
4 cards from a deck and 2 of them are hearts 2 are diamonds and the diamonds are next to each other and the sum equals 11 and 1 card is than the sum of 2 cards an no aces what are the cards order?
2 of hearts, 2 of diamonds, 3 of diamonds, and 4 of hearts
Probability of dealing ace king and queen of spades in that order when dealing only 3 cards?
The probability of dealing the Ace of Spades from a normal 52 card deck is 1 in 52. The probability of dealing the King of Spades next is 1 in 51. The probability of dealing the Queen of Spades next is 1 in 50.The probability of drawing those three cards in that order is the product of those probabilities, which is 1 in 132,600. This is the same as the number of permutations of N (52) things taken P (3) at a time, which is stated as N! - P! (52 * 51 * 50)If you did not care what order the cards were dealt in, but still wanted to know the probability of getting the Ace, King, and Queen of Spades, then you would be talking about the combinations of N (52) things taken P (3) at a time, which is stated as (N! - P!) / (N - P)! (52 * 51 * 50 / 3 / 2 / 1). The probability in this case is 1 in 22,100.
If you select two cards from a deck of 52 cards what is the probability that the first card is an 6 of diamaond and the second card is an 3 of hearts?
First off, how do I calculate the probability that any one event occurs. The answer is equal to: Number of Possible Chances of Success / Total Number of Chances In this case, the number of possible chances of success is one (there is only one 6 of Diamonds in any deck of cards). The total number of chances equal 52 (there are 52 cards to choose from). Therefore the probability of picking a 6 of Diamonds on the first card is 1/52 or .019. In order to calculate the probability that the first card is a 6 of Diamonds AND the second card is a 3 of Hearts, you multiply the two probabilities. Prob. of 1st Card 6D AND 2nd Card 3H = Prob. 1st Card 6D * Prob. 2nd Card 3H We already know the probability of getting a 6 of Diamonds on the first card is 1/52 or .019. To calculate the probability of getting a 3 of Hearts on the second card, it is important to remember that random occurances do not affect the probability of other random occurrances. What I mean is, if I were to draw a 6 of Diamonds from a deck of cards and then replace it, the probability that I would pick a 6 of Diamonds again is the same as it was the first time. Even if I flip a coin 5 times in a row and they all landed on heads, the probability that I would flip another heads is still 50/50. So basically we can ignore what happened on the first draw, and jsut calculate the probability of getting a 3 of Hearts. Again we use our probability formula: Number of Possible Chances of Success / Total Number of Chances In this case, the number of possible chances of success is one (there is only one 3 of Hearts in any deck of cards). The total number of chances equal 52 (THIS ASSUMES THAT WE PUT THE 6 OF DIAMONDS BACK INTO THE DECK AFTER THE FIRST DRAW IF NOT THE NUMBER OF CHANCES IS 51). Therefore the probability of picking a 3 of Hearts on the second card is 1/52 or .019. Multiply the two probabilities together to get the probability of both occurring: 1/52 * 1/52 = 1/2704 = .00037 (or a .037 percent of a chance)
