There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes.
However, if you assume that they are independent events then, given that the probability of a girl is approx 0.48, the probability of three out of three being girls is 0.1127.
there is a 50% chance that two of them will be girls
50/50
It is 3/8.
2/6 is not accurate. using a theoretical method for equally likely outcomes, there are 2 possible outcomes for each birth: either a boy(B), or a girl (G). For a family of three children, the total number of possibilities (birth orders) is 2*2*2=8 to double check this work, here are the eight possible outcomes:BBB, BBG, BGG, GBB, GBG, GGB, and GGG. You want EXACTLY two girls, this assumes that the other must be a boy. Therefore, the probability that a three child family has 2 girls one boy is P(2 girls)=3/8=0.375
The probability is 90/216 = 5/12
there is a 50% chance that two of them will be girls
50/50
It is 3/8.
Assuming that having boys and girls are equally likely, then the probability is 1/8. * * * * * You also need to assume that the children's genders are independent. They are NOT and depend on the parents' ages and genes.
Assuming that children of either gender are equally likely, the answer is (1/2)3 = 1/8
Yes, grandparents had exactly three boys (including my dad) and three girls.
2/6 is not accurate. using a theoretical method for equally likely outcomes, there are 2 possible outcomes for each birth: either a boy(B), or a girl (G). For a family of three children, the total number of possibilities (birth orders) is 2*2*2=8 to double check this work, here are the eight possible outcomes:BBB, BBG, BGG, GBB, GBG, GGB, and GGG. You want EXACTLY two girls, this assumes that the other must be a boy. Therefore, the probability that a three child family has 2 girls one boy is P(2 girls)=3/8=0.375
you have a 75% chance
The probability is 90/216 = 5/12
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes.If you believe that the children's genders are not independent then you would need to get empirical evidence from all families with four or more children in which the first three children were girls. If there are g families in which the fourth is a girl and b where the fourth is a boy then the required probability is b/(g+b).However, if you assume that the children's genders are independent events then, given that the probability of a boy is approx 0.52, the probability of the fourth child is a boy is 0.52
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes. However, if you assume that they are independent events then, given that the probability of a boy is approx 0.52, the probability that all three children are boys is approx 0.1381
The answer to this is 1 minus the probability that they will have 3 or fewer children. This would happen only if they had a boy as the first, second or third child. The probability they have a boy as first child is 0.5 The probability they have a boy as second is 0.25 The probability they have a boy as third is 0.125 Thus the total probability is 0.875 And so the probability they will have more than three children is 1-0.875 or 0.125