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What is the probability of getting HTTH in a sequence of 4 coin tosses?
Irela001
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What is the sample space of tossing 4 coins?
If the order of the outcomes matters, then TTTT, TTTH, TTHT, THTT, HTTT, TTHH, THTH, THHT, HTTH, HTHT, HHTT, THHH, HTHH, HHTH, HHHT, HHHH. If the order does not matter, then TTTT, TTTH, TTHH, THHH AND HHHH
How do you find the probability distribution of x if a fair coin is tosses four times and x is the PRODUCT of the number of heads times the number of tails?
There are 16 possible outcomes, each of which is equally likely. So each has a probability of 1/16 HHHH: X = H*T = 4*0 = 0 HHHT: X = H*T = 3*1 = 3 HHTH: X = H*T = 3*1 = 3 HTHH: X = H*T = 3*1 = 3 THHH: X = H*T = 3*1 = 3 HHTT: X = H*T = 2*2 = 4 HTHT: X = H*T = 2*2 = 4 HTTH: X = H*T = 2*2 = 4 THHT: X = H*T = 2*2 = 4 THTH: X = H*T = 2*2 = 4 TTHH: X = H*T = 2*2 = 4 HTTT: X = H*T = 1*3 = 3 THTT: X = H*T = 1*3 = 3 TTHT: X = H*T = 1*3 = 3 TTTH: X = H*T = 1*3 = 3 TTTT: X = H*T = 0*4 = 0 So, the probability distribution function of X is f(X = 0) = 1/16 f(X = 1) = 4/16 = 1/4 f(X = 2) = 6/16 = 3/8 f(X = 3) = 4/16 = 1/4 f(X = 4 = 1/16 and f(X = x) = 0 for all other x
What is the sample space of tossing a coin 4 times?
The term 'sample space' can be somewhat arbitrary. In this case, it might be any of the following (or another) possibility: If order of flips is significant: HHHH HHHT HHTH HHTT HTHH HTHT HTTH HTTT THHH THHT THTH THTT TTHH TTHT TTTH TTTT If order is not significant: HHHH HHHT HHTT HTTT TTTT If, say, only the number of either heads or tails is important: 4 3 2 1
What is the probability that on 4 flips of a coin 3 will be heads and1 will be tails?
There are 16 permutations of a coin tossed 4 times. They are ...HHHH - HHHT - HHTH - HHTTHTHH - HTHT - HTTH - HTTTTHHH - THHT - THTH - THTTTTHH - TTHT - TTTH - TTTT... and the permutations with only one tail are bolded. There are 4, so the probability of flipping a coin 4 times and getting only 1 tail is 4 in 16, or 1 in 4, or 0.25.The coin does not have a memory therefore the probability is always 50/50.
What is the P(HTTH) on four consecutive flips of a coin?
It is 1/16.
What is the sample space of tossing a coin 4x?
HHHH, HHHT, HHTH, HHTT, HTHH, HTHT, HTTH, HTTT THHH, THHT, THTH, THTT, TTHH, TTHT, TTTH, TTTT
If you flip a coin 4 times what are all of the outcomes?
HHHH, HHHT, HHTH, HTHH, THHH, HHTT, HTHT, HTTH, THHT, THTH, TTHH, HTTT, THTT, TTHT, TTTH, TTTT.
What is the sample space of tossing 4 coins?
If the order of the outcomes matters, then TTTT, TTTH, TTHT, THTT, HTTT, TTHH, THTH, THHT, HTTH, HTHT, HHTT, THHH, HTHH, HHTH, HHHT, HHHH. If the order does not matter, then TTTT, TTTH, TTHH, THHH AND HHHH
How do you find the probability distribution of x if a fair coin is tosses four times and x is the PRODUCT of the number of heads times the number of tails?
There are 16 possible outcomes, each of which is equally likely. So each has a probability of 1/16 HHHH: X = H*T = 4*0 = 0 HHHT: X = H*T = 3*1 = 3 HHTH: X = H*T = 3*1 = 3 HTHH: X = H*T = 3*1 = 3 THHH: X = H*T = 3*1 = 3 HHTT: X = H*T = 2*2 = 4 HTHT: X = H*T = 2*2 = 4 HTTH: X = H*T = 2*2 = 4 THHT: X = H*T = 2*2 = 4 THTH: X = H*T = 2*2 = 4 TTHH: X = H*T = 2*2 = 4 HTTT: X = H*T = 1*3 = 3 THTT: X = H*T = 1*3 = 3 TTHT: X = H*T = 1*3 = 3 TTTH: X = H*T = 1*3 = 3 TTTT: X = H*T = 0*4 = 0 So, the probability distribution function of X is f(X = 0) = 1/16 f(X = 1) = 4/16 = 1/4 f(X = 2) = 6/16 = 3/8 f(X = 3) = 4/16 = 1/4 f(X = 4 = 1/16 and f(X = x) = 0 for all other x
What is the sample space of tossing a coin 4 times?
The term 'sample space' can be somewhat arbitrary. In this case, it might be any of the following (or another) possibility: If order of flips is significant: HHHH HHHT HHTH HHTT HTHH HTHT HTTH HTTT THHH THHT THTH THTT TTHH TTHT TTTH TTTT If order is not significant: HHHH HHHT HHTT HTTT TTTT If, say, only the number of either heads or tails is important: 4 3 2 1
