# of diamond card = 13 # of black 7 card = 2 P(diamond and black 7) = 13/52 * 2/51 = 1/4 * 2/51 Answer = 1/102
First we find the probability of getting a 7. Of the 36 outcomes possible 6 result in a sum of 7, in other words 1/6. The probability of getting an 11 is 2/36 or 1/18. The probability of getting one or the other is the sum of the two, 8/36 or 2/9. The proability of getting neither is equal to the probability of getting anything other than 7 or 8. We find this value by subtracting 2/9 from 1. So the probability of not getting 7 or 11 is 7/9.
If it is a fair coin, the probability of getting at least one Head from 3 flips is 7/8If it is a fair coin, the probability of getting at least one Head from 3 flips is 7/8If it is a fair coin, the probability of getting at least one Head from 3 flips is 7/8If it is a fair coin, the probability of getting at least one Head from 3 flips is 7/8
To calculate the probability of drawing a black card and a 7 from a standard deck of 52 cards, we first determine the total number of black cards and the number of 7s in the deck. There are 26 black cards (13 spades and 13 clubs) and 4 sevens in the deck. The probability of drawing a black card and a 7 is calculated by multiplying the probability of drawing a black card (26/52) by the probability of drawing a 7 (4/52), resulting in a probability of (26/52) * (4/52) = 1/26 or approximately 0.0385.
Probability of drawing a black 7 from a standard 52-card deck is 2/52 or 1/26.
# of diamond card = 13 # of black 7 card = 2 P(diamond and black 7) = 13/52 * 2/51 = 1/4 * 2/51 Answer = 1/102
There is a .53846 probability (53.846%) if aces are counted as face cards. If they are not counted the probability drops to .48077 (48.077%)
The probability is 7/36
7 in 12, or about 0.5833.
First we find the probability of getting a 7. Of the 36 outcomes possible 6 result in a sum of 7, in other words 1/6. The probability of getting an 11 is 2/36 or 1/18. The probability of getting one or the other is the sum of the two, 8/36 or 2/9. The proability of getting neither is equal to the probability of getting anything other than 7 or 8. We find this value by subtracting 2/9 from 1. So the probability of not getting 7 or 11 is 7/9.
The probability of getting a 7 on one roll of a die is zero.If you meant to ask about two dice, the probability is 6 in 36, or 1 in 6.
If it is a fair coin, the probability of getting at least one Head from 3 flips is 7/8If it is a fair coin, the probability of getting at least one Head from 3 flips is 7/8If it is a fair coin, the probability of getting at least one Head from 3 flips is 7/8If it is a fair coin, the probability of getting at least one Head from 3 flips is 7/8
On a single roll of a normal die the probability of getting a 7 is 0.
Probability that the sum is 6 = 5/36 Probability that the sum is 7 = 6/36
To calculate the probability of drawing a black card and a 7 from a standard deck of 52 cards, we first determine the total number of black cards and the number of 7s in the deck. There are 26 black cards (13 spades and 13 clubs) and 4 sevens in the deck. The probability of drawing a black card and a 7 is calculated by multiplying the probability of drawing a black card (26/52) by the probability of drawing a 7 (4/52), resulting in a probability of (26/52) * (4/52) = 1/26 or approximately 0.0385.
The probability of getting only one tails is (1/2)7. With seven permutations of which flip is the tails, this gives a probability of: P(six heads in seven flips) = 7*(1/2)7 = 7/128
The probability of getting on the first draw a black ball is: P(B1) = 3/7. The probability of getting a red ball given the event of drawing a black ball on the first draw is: P(R2│B1) = 4/6. The probability of drawing a black ball on the first draw and a red ball on the second draw is: P(B1UR2) = P(B1)∙P(R 2│B1) = (3/7)∙(4/6) = 0.2857... ~ 0.286 ~ ~ 28.6%