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The probability of getting a diamond and a black seven is zero. Diamonds are red.
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What is the probability of drawing a diamond and a black seven in a deck of 52 cards?
# of diamond card = 13 # of black 7 card = 2 P(diamond and black 7) = 13/52 * 2/51 = 1/4 * 2/51 Answer = 1/102
What is the probability of not getting a 7 or 11 on either of two tosses of a pair of dice?
First we find the probability of getting a 7. Of the 36 outcomes possible 6 result in a sum of 7, in other words 1/6. The probability of getting an 11 is 2/36 or 1/18. The probability of getting one or the other is the sum of the two, 8/36 or 2/9. The proability of getting neither is equal to the probability of getting anything other than 7 or 8. We find this value by subtracting 2/9 from 1. So the probability of not getting 7 or 11 is 7/9.
What is the probability of flipping a head when you roll a coin 3 times?
If it is a fair coin, the probability of getting at least one Head from 3 flips is 7/8If it is a fair coin, the probability of getting at least one Head from 3 flips is 7/8If it is a fair coin, the probability of getting at least one Head from 3 flips is 7/8If it is a fair coin, the probability of getting at least one Head from 3 flips is 7/8
What is the probability of drawing a black card and a 7?
1/26
What is the probability of drawing a black 7 from a standard 52-card deck?
Probability of drawing a black 7 from a standard 52-card deck is 2/52 or 1/26.
What is the probability of drawing a diamond and a black seven in a deck of 52 cards?
# of diamond card = 13 # of black 7 card = 2 P(diamond and black 7) = 13/52 * 2/51 = 1/4 * 2/51 Answer = 1/102
What is the probability of getting a face card or a 7 or a diamond from an ordinary deck of cards?
There is a .53846 probability (53.846%) if aces are counted as face cards. If they are not counted the probability drops to .48077 (48.077%)
What is the probability of getting a multiple of 5 when rolling 2 dice?
The probability is 7/36
What is the probability of getting a 7 on a dodecahedron?
7 in 12, or about 0.5833.
What is the probability of not getting a 7 or 11 on either of two tosses of a pair of dice?
First we find the probability of getting a 7. Of the 36 outcomes possible 6 result in a sum of 7, in other words 1/6. The probability of getting an 11 is 2/36 or 1/18. The probability of getting one or the other is the sum of the two, 8/36 or 2/9. The proability of getting neither is equal to the probability of getting anything other than 7 or 8. We find this value by subtracting 2/9 from 1. So the probability of not getting 7 or 11 is 7/9.
What is the probability of getting a 7 on one roll of a die?
The probability of getting a 7 on one roll of a die is zero.If you meant to ask about two dice, the probability is 6 in 36, or 1 in 6.
What is the probability of flipping a head when you roll a coin 3 times?
If it is a fair coin, the probability of getting at least one Head from 3 flips is 7/8If it is a fair coin, the probability of getting at least one Head from 3 flips is 7/8If it is a fair coin, the probability of getting at least one Head from 3 flips is 7/8If it is a fair coin, the probability of getting at least one Head from 3 flips is 7/8
What are the probabilities of getting a 7?
On a single roll of a normal die the probability of getting a 7 is 0.
When two dice are rolled find the probability of getting a 6 or 7?
Probability that the sum is 6 = 5/36 Probability that the sum is 7 = 6/36
What is the probability of tossing seven coins and getting 6 heads?
The probability of getting only one tails is (1/2)7. With seven permutations of which flip is the tails, this gives a probability of: P(six heads in seven flips) = 7*(1/2)7 = 7/128
What is the probability of drawing a black card and a 7?
1/26
There are 7 balls in a box 3 black and 4 red a ball will be drawn and not replacecd then a second ball wil lbe drawn what is the chances it will be a black ball and then red ball?
The probability of getting on the first draw a black ball is: P(B1) = 3/7. The probability of getting a red ball given the event of drawing a black ball on the first draw is: P(R2│B1) = 4/6. The probability of drawing a black ball on the first draw and a red ball on the second draw is: P(B1UR2) = P(B1)∙P(R 2│B1) = (3/7)∙(4/6) = 0.2857... ~ 0.286 ~ ~ 28.6%
