The probability of getting a diamond and a black seven is zero. Diamonds are red.
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# of diamond card = 13 # of black 7 card = 2 P(diamond and black 7) = 13/52 * 2/51 = 1/4 * 2/51 Answer = 1/102
First we find the probability of getting a 7. Of the 36 outcomes possible 6 result in a sum of 7, in other words 1/6. The probability of getting an 11 is 2/36 or 1/18. The probability of getting one or the other is the sum of the two, 8/36 or 2/9. The proability of getting neither is equal to the probability of getting anything other than 7 or 8. We find this value by subtracting 2/9 from 1. So the probability of not getting 7 or 11 is 7/9.
If it is a fair coin, the probability of getting at least one Head from 3 flips is 7/8If it is a fair coin, the probability of getting at least one Head from 3 flips is 7/8If it is a fair coin, the probability of getting at least one Head from 3 flips is 7/8If it is a fair coin, the probability of getting at least one Head from 3 flips is 7/8
To calculate the probability of drawing a black card and a 7 from a standard deck of 52 cards, we first determine the total number of black cards and the number of 7s in the deck. There are 26 black cards (13 spades and 13 clubs) and 4 sevens in the deck. The probability of drawing a black card and a 7 is calculated by multiplying the probability of drawing a black card (26/52) by the probability of drawing a 7 (4/52), resulting in a probability of (26/52) * (4/52) = 1/26 or approximately 0.0385.
Probability of drawing a black 7 from a standard 52-card deck is 2/52 or 1/26.