There are 36 permutations of two dice.1 Of these 4 have a sum of 9, specifically 36, 45, 54, and 63. Therefore, the probability of throwing a sum of 9 on two dice is 4 in 36, or 1 in 9, or about 0.1111.
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1It does not matter it you throw one die two times or two dice once. Since these are independent events, the probabilities are the same either way.
Two standard dice cannot have a sum greater than 12. The probability, then, of getting a sum greater than 15 is zero.
5/36
You can't get 14 with two regular six-sided dice ! The highest you can get with one throw is 12.
It is 1/6.
33,33333...%
The probability is zero. The largest possible sum on two dice is 12.
Two standard dice cannot have a sum greater than 12. The probability, then, of getting a sum greater than 15 is zero.
Assuming these are regular dice, the probability is 1.
It is 5/36.
The probability of rolling 12 with 2 dice is 1 in 36. The probability of not rolling 12 with 2 dice is 35 in 36.
With two normal six-sided dice, the maximum sum can only be 12 (6 x 2 dice), so there is zero probability of rolling a sum that adds to 16.
5/36
35/36
Probability that the sum is 6 = 5/36 Probability that the sum is 7 = 6/36
The probability of getting a sum of 2 at least once is 0.8155
You can't get 14 with two regular six-sided dice ! The highest you can get with one throw is 12.
The first thing to do is isolate how many ways there are to get 8 from two dice. These possibilities are:2,63,54,45,36,2so there are 5 possibilities. The probability of each of these combinations is (1/6)2 or 1/36, so the probability of getting 8 in one throw of 2 dice is 5/36For 9 throws, it is easier to calculate the probability of never getting 8. This is (1-probability of getting 8)9. (1-5/36)9 = (31/36)9 which is 0.26033. So the probability of getting an 8 somewhere along the line is 1-0.26033 or 0.7397