There are 30 possible combinations of die rolls (assuming 2 6-sided die) (excluding "doubles")
The highest total you can get is 12 so the numbers you are after are 10,11 and 12...
The possible combos which add to greater than 9 are:
4,6
6,4
5,5
5,6
6,5
So the probability of rolling a 10, 11 or 12 is 5:30 (5 times out of 30 rolls)
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Two standard dice cannot have a sum greater than 12. The probability, then, of getting a sum greater than 15 is zero.
Probably.
It is 1/6.
When rolling one die, the probability of getting a 4 is 1 in 6, or 0.1667. If two dice are rolled, you get two unrelated chances of rolling at least one 4, so the probability is 2 in 6, or 0.3333.
These are independent one has no bearing on the other
Two standard dice cannot have a sum greater than 12. The probability, then, of getting a sum greater than 15 is zero.
If they are normal dice, the probability is 0.
It is 15/36 = 5/12
It is 5 over 6.
Assuming these are regular dice, the probability is 1.
The probability of rolling 12 with 2 dice is 1 in 36. The probability of not rolling 12 with 2 dice is 35 in 36.
The probability is 35/36.
The probability is 1, if the dice are rolled often enough.
Probably.
The probability is 8/36 or 2/9
It is 1/6.
1/12 or .083