The answer depends on how many cards are drawn and whether or not they are replaced before the next card is drawn.
The answer depends on how many cards are drawn and whether or not they are replaced before the next card is drawn.
The answer depends on how many cards are drawn and whether or not they are replaced before the next card is drawn.
The answer depends on how many cards are drawn and whether or not they are replaced before the next card is drawn.
The probability of getting the queen of hearts is 1 in 52, or about 0.01923. The probability of getting any queen is 4 in 52, or about 0.07692. The probability of getting any heart is 13 in 52, or exactly 0.25.
The probability of drawing a red heart is 1 in 4. This is the same as the probability of drawing a heart, as red is included as a superset of hearts.
(question not clear) , as far to my understanding it is 4 over 52 simplified , so answer is = 1 over 13. (probability of a king drawn from a pack of cards)
It is 1/52.
The probability of pulling a king of hearts in one random selection from a well shuffled normal deck of cards is 1/52.
The probability of drawing a king of hearts from a regular deck of cards is 1 in 52 because there is only one king of hearts in the standard 52 card deck.
The probability of getting two hearts in a row: P(Getting a hearts on the first draw)*P(Getting another hearts given the first one was a hearts) The first probability is simple: there are 13 hearts in a deck of 52 cards. The probability is 13/52=1/4. The second probability is trickier: there are now 12 hearts left in a deck of 51 cards! The probability of getting another hearts is therefore 12/51=4/17. Now compute (1/4)*(4/17) and get 1/17, which is the probability of drawing two hearts from a deck of fifty-two playing cards.
The probability of getting the queen of hearts is 1 in 52, or about 0.01923. The probability of getting any queen is 4 in 52, or about 0.07692. The probability of getting any heart is 13 in 52, or exactly 0.25.
The probability of drawing a red heart is 1 in 4. This is the same as the probability of drawing a heart, as red is included as a superset of hearts.
With a regular deck (2-Ace with ♥,♦,♣, and ♠), the probability of drawing a three is 1 in 13. The probability for a heart is 1 in 4, a.k.a. 25% or 1/4 . The probability for a 3 of hearts is 1 in 52.Improve:And to be more specific:because a heart is 25%, and a three is 4/52 % and the h of hearts is 1/52 getting a 3 OR heart is 25% (heart) + 7.69% (a 3) - 1.923% (3 of hearts can't be counted twice!) = .30767
The answer depends on how many cards are drawn, whether they are drawn at random and whether they are replaced before drawing the next card. If three cards are drawn, at random and without replacement, the probability that they are hearts is (13/52)*(12/51)*(11*50) = 1716/132600 = 0.0129
The probability of drawing the Five of Hearts from a standard deck of 52 cards is 1 in 52, or about 0.01923.
The probability of getting a particular suit (hearts, spades, diamonds, clubs) is 1 in 4. The probability of getting a card less than 8 (2, 3, 4, 5, 6, 7) is 6 in 13. The probability, then, of getting a particular suit less than 8 is (1 in 4) times (6 in 13) or 6 in 52 or 3 in 26.
The probability of picking a 23 of hearts in a standard 52 card deck of cards is zero, because there is no 23 of hearts. If you meant to ask about the probability of picking a 2 or a 3 of hearts, then the probability is 2 in 52, or 1 in 26, or about 0.03846.
The probability of getting one heart in a random draw from a 52 card deck is 13 in 52, or 1 in 4. The probability of getting the second heart is 12 in 51 - the third, 11 in 50 - the fourth, 10 in 49. The total probability of getting four hearts is simply the product of those probabilities, or 1320 in 499800. Simplified to least common multiple, that reduces to 11 in 4165.
(question not clear) , as far to my understanding it is 4 over 52 simplified , so answer is = 1 over 13. (probability of a king drawn from a pack of cards)
If only two cards are drawn randomly from a standard deck, the probability is .00037, approx.