Q: What is the probability of landing the 5 of hearts?

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Probability of a spinner of 20 landing on 5 is 1/20.

Probability (P)of drawing 5 hearts (H) is: P(H) and P(H) and P(H) and P(H) and P(H). There are 13 hearts in a 52 card deck. So, probability is: 13/52 * 12/51 * 11/50 * 10/49 * 9/48 or 154440/311875200 or 0.000495.

The probability of getting two hearts in a row: P(Getting a hearts on the first draw)*P(Getting another hearts given the first one was a hearts) The first probability is simple: there are 13 hearts in a deck of 52 cards. The probability is 13/52=1/4. The second probability is trickier: there are now 12 hearts left in a deck of 51 cards! The probability of getting another hearts is therefore 12/51=4/17. Now compute (1/4)*(4/17) and get 1/17, which is the probability of drawing two hearts from a deck of fifty-two playing cards.

Since there are 6 possible outcomes, and you want the probability of obtaining one of the outcomes (in your case 6), the probability of it landing on a 6 is 1/6.

1/2 * 1/2 = 1/4 1/2= probability of landing an even number 1/2 = probability of landing a heads

Related questions

Probability of a spinner of 20 landing on 5 is 1/20.

The probability of a fair coin landing on tails is 0.5. The probability of 4 tails is .5*5*.5*.5 = 0.0625.

the probability of tossing a coin and it landing on head is a 1 in 2 chance the probability of rolling a 5 on a dice is a 1 in 6 chance

The probability that both coins are heads is the probability of one coin landing heads multiplied by the probability of the second coin landing heads: (.5) * (.5) = .25 or (1/2) * (1/2) = 1/4

The probability of a coin landing head-side down is 0.5 The probability of landing head-side up is 0.5 Did you mean to ask the probability of it landing on its edge ?

What is the probability of the spinner landing on CorB

On a 6-sided die, the probability of not having a six is 5/6, or 83 1/3 %

The probability is 5/9.

Experimental probability is calculated by taking the data produced from a performed experiment and calculating probability from that data. An example would be flipping a coin. The theoretical probability of landing on heads is 50%, .5 or 1/2, as is the theoretical probability of landing on tails. If during an experiment, however, a coin is flipped 100 times and lands on heads 60 times and tails 40 times, the experimental probability for this experiment for landing on heads is 60%, .6 or 6/10. The experimental probability of landing on tails would be 40%, .4, or 6/10.

Probability (P)of drawing 5 hearts (H) is: P(H) and P(H) and P(H) and P(H) and P(H). There are 13 hearts in a 52 card deck. So, probability is: 13/52 * 12/51 * 11/50 * 10/49 * 9/48 or 154440/311875200 or 0.000495.

The probability of landing on heads each time a fair coin is flipped, is 1/2.Assuming that the question was supposed to be:"What is the probability of landing on heads twice in a row?"To calculate compound probabilities like this, we first have to work out the probability of landing on heads each time, and then multiply these two probabilities to get a compound probability.1/2 x 1/2 = 1/4So the probability of landing on heads twice in a row = 1/4 (for a fair coin)

The probability of getting two hearts in a row: P(Getting a hearts on the first draw)*P(Getting another hearts given the first one was a hearts) The first probability is simple: there are 13 hearts in a deck of 52 cards. The probability is 13/52=1/4. The second probability is trickier: there are now 12 hearts left in a deck of 51 cards! The probability of getting another hearts is therefore 12/51=4/17. Now compute (1/4)*(4/17) and get 1/17, which is the probability of drawing two hearts from a deck of fifty-two playing cards.