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Oh, dude, the probability of guessing the last digit of a phone number is 1 in 10, because there are 10 possible digits (0-9). So, like, if you randomly guess, you have a 10% chance of getting it right. But hey, don't stress about it too much, it's just a phone number!

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It is 1/10.

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Wiki User

10y ago
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Q: What is the probability of guessing the last digit of a phone number?
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What is the probability that a seven-digit phone number contains the number 7?

Best way to answer this question is by figuring out the probability of a phone number not containing the number 7. There are 9 other numbers that are not a 7, so odds of each digit not being a 7 is 90%. For a 7-digit number, calculation would be 0.9*0.9*0.9*0.9*0.9*0.9*0.9 or 0.9^7. This equals 47.8%, which means the odds of a phone number containing at least one 7 is 100% - 47.8%, which is 52.2%. But phone numbers do not begin with 0 or 1, so if we account for that, the odds of the first digit not being a 7 is 7/8, not 9/10. We replace the first 0.9 with 0.875, and the result is 53.5%. There are other scenarios we can take out, like numbers that begin with 555, but I'll just leave it at that.


A complete probability distribution is always an objective listing of all possible events Since it is impossible to list all the possible outcomes from a single event probability distributions are o?

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How many digits does a phone number have?

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If a digital combination lock on a phone has 4 spaces with digits 0 to 9. How many 4 digit combination lock codes are possible?

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