No, my second to last phone number ended in 3836.
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To find the last but one digit in the product of the first 75 even natural numbers, we need to consider the units digit of each number. Since we are multiplying even numbers, the product will end in 0. Therefore, the last but one digit (tens digit) will depend on the multiplication of the tens digits of the numbers. The tens digit will be determined by the pattern of the tens digits of the even numbers being multiplied.
Oh, dude, there are 90 three-digit palindromic numbers. You see, a three-digit palindrome has the form "ABA," where A and B can be any digit from 1 to 9. So, you just multiply the possibilities for A and B, which is 9 choices each, and voilà, you get 9 x 10 = 90. Easy peasy, lemon squeezy!
You end it when all the numbers are prime.
All even numbers are divisible by 2. The even numbers are those numbers which end with one of the digits {0, 2, 4, 6, 8}.
All even numbers (numbers evenly divisible by 2) will end with 2, 4, 6, 8, or 0.