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If there are 3 red 4 blue and 5 yellow marbles what is the probability of pulling a red or blue marble vs the probability of pulling a red marble the first time and a blue marble the second time?
Wiki User
∙ 7y ago
Pr(Red or Blue) = 0.5833...Pr(R on first pull and Blue on second pull) = 0.0533...
Wiki User
∙ 7y ago
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A bag contains 6 purple and 7 white marbles two marbles are drawn at random one marble is drawn and not replaced what is the probability that the fist marble is white and the second is purple?
2/13
What is the probability of drawing a white marble then a red marble if there are 3 red marbles and 2 white marbles?
5 marbles. 3 red marbles, 2 white marbles.The probability of drawing a white marble is P(W) = 2/5 = 0.40If the white marble is not returned to the rest of the marbles (no substitution), theprobability that the second marble drawn is a red one is P(R) = 3/4 = 0.75.The probability that the event of drawing first a white marble and without substitutionthe second draw turns a red marble is P(1stW,2ndR) = (2/5)∙(3/4) = 6/20 = 3/10 = 0.30 = 30.0%.If the process of drawing the marbles is with substitution, the probability of thesecond draw turning a red marble is P(R) = 3/5 = 0.60 = 60.0%The probability that the event of first drawing a white marble and after returning themarble back to the original group of marbles (with substitution) the second draw turns a red marble is P(1stW,2ndR) = (2/5)∙(3/5) = 6/25 = 0.24 = 24.0%.
If A bag contains 3 orange 5 black and 2 white marbles Two marbles are drawn but the first marble is not replaced Find P white then black?
Bag with 10 marbles: 3 orange, 5 black, 2 white.Rephrasing the question.If a marble is drawn from the bag, then returned to the bag, and a second marbleis drawn, what is the probability that the first marble turns out white and the secondmarble black ?The probability for a marble to come out white from the bag is:P(W) = 2/10 = 1/5The probability for a marble to come out black from the bag is:P(B) = 5/10 = 1/2The probability for a marble to come out white, put back in the bag and then take again a marble for a second time and turns out to be black is:P(B2|W1) = (1/5)∙(1/2) = 1/10 = 0.10 = 10 %
If you have 50 black marbles and 50 white marbles in a bag at most how many times would you have to draw out a marble to get two the same colour?
The maximum number of marbles you have to draw is three. 1) Draw a marble. It is either white or black. 2) Draw a second marble. If it is the same colour as the first marble, we are done after two draws. 3) Otherwise, the drawn marbles have different colours. Draw a third marble. No matter what you draw next, you must have two marbles of the same colour.
A bag contains 6 red marbles 9 blue marbles and 5 green marbles You withdraw one marble replace it and withdraw another marble What is the probability that you do not draw two green marbles 25 denomo?
Because you are replacing the marbles then it is an independent event. P(1st one is not green) = 1 - P(first green), equally P(2nd one is not green) = 1 - (second green), Thus it reads P(¬G ^ ¬G) = P(¬G) * P(¬G) = 15/20 * 15/20 = 225/400 = 9/16
In a bag there are 4 red marbles 5 white marbles and 6 blue marbles once a marble is selected it is not replaced what are the odds of pulling a red marble than a white marble?
The odds of pulling a red marble on the first try is 4/15 or about .27 and the probability of drawing a white marble the second time if a the first is a red marble is 5/14 or about .36. the odds of both happening is the product of the probabilities of the other events, or 2/21.
A bag contains 6 purple marbles and 7 white marbles Two marbles are drawn at random One marble is drawn and not replaced Then a second marble is drawn What is the probability that the first marble?
There are 13 marbles in total. The order is specified.P(1st is white and the 2ndis purple) = (7/13)(6/12) = (7/13)(1/2) = 7/26.
What is the independent and dependent event for pulling two marbles out of a bag?
The first marble is the independent event because its probability is only based on the sample space of the bag. The second marble is the dependent event because its probability is based on the sample space of the bag which has now been changed by the first marble.
If A bag contains 3 red marbles and 5 purple marbles One marble is drawn at random and not replaced Then a second marble is drawn at random What is the probability that the first marble is purple and?
3/5
A bag contains 6 purple and 7 white marbles two marbles are drawn at random one marble is drawn and not replaced what is the probability that the fist marble is white and the second is purple?
2/13
What is the probability of drawing a white marble then a red marble if there are 3 red marbles and 2 white marbles?
5 marbles. 3 red marbles, 2 white marbles.The probability of drawing a white marble is P(W) = 2/5 = 0.40If the white marble is not returned to the rest of the marbles (no substitution), theprobability that the second marble drawn is a red one is P(R) = 3/4 = 0.75.The probability that the event of drawing first a white marble and without substitutionthe second draw turns a red marble is P(1stW,2ndR) = (2/5)∙(3/4) = 6/20 = 3/10 = 0.30 = 30.0%.If the process of drawing the marbles is with substitution, the probability of thesecond draw turning a red marble is P(R) = 3/5 = 0.60 = 60.0%The probability that the event of first drawing a white marble and after returning themarble back to the original group of marbles (with substitution) the second draw turns a red marble is P(1stW,2ndR) = (2/5)∙(3/5) = 6/25 = 0.24 = 24.0%.
A bag contains 8 marbles 4 are blue 3 are green and one is orange you draw out one marble and then another without replacing the first marble Find the probability of drawing 2 blue marbles?
Probability of drawing a blue marble first is 4 in 8 (or 50%) Probability of drawing a blue marble second is 3 in 7 (or 42.85714%) Probablility of drawing blue then blue is the two above multiplied 0.5 * 0.4285714 Which is 0.212142407 or 21% or One in Five.
If A bag contains 3 orange 5 black and 2 white marbles Two marbles are drawn but the first marble is not replaced Find P white then black?
Bag with 10 marbles: 3 orange, 5 black, 2 white.Rephrasing the question.If a marble is drawn from the bag, then returned to the bag, and a second marbleis drawn, what is the probability that the first marble turns out white and the secondmarble black ?The probability for a marble to come out white from the bag is:P(W) = 2/10 = 1/5The probability for a marble to come out black from the bag is:P(B) = 5/10 = 1/2The probability for a marble to come out white, put back in the bag and then take again a marble for a second time and turns out to be black is:P(B2|W1) = (1/5)∙(1/2) = 1/10 = 0.10 = 10 %
A bag that has 7 greens marbles 3 blue marbles and 12 white marbles what is the probability of selecting a white marble on each of the three tries if the marble is placed back after each pick?
12 white marbles from (7+3+12) = 22 marblesChance of a white marble on first pick = 12/22 = 6/11.Chance of a white marble on second and third picks are the same, as the marble is replaced.So, the chance of a white marble three times is 6/11 * 6/11 * 6/11 = 216/1331 = approximately 16.23%
If you have 50 black marbles and 50 white marbles in a bag at most how many times would you have to draw out a marble to get two the same colour?
The maximum number of marbles you have to draw is three. 1) Draw a marble. It is either white or black. 2) Draw a second marble. If it is the same colour as the first marble, we are done after two draws. 3) Otherwise, the drawn marbles have different colours. Draw a third marble. No matter what you draw next, you must have two marbles of the same colour.
A bag contains 6 red marbles 9 blue marbles and 5 green marbles You withdraw one marble replace it and withdraw another marble What is the probability that you do not draw two green marbles 25 denomo?
Because you are replacing the marbles then it is an independent event. P(1st one is not green) = 1 - P(first green), equally P(2nd one is not green) = 1 - (second green), Thus it reads P(¬G ^ ¬G) = P(¬G) * P(¬G) = 15/20 * 15/20 = 225/400 = 9/16
If you have a bag of 4 red and 4 green marbles what is the probability of drawing 2 marbles without replacement and getting 2 green marbles?
4/8 or 1/2(probability of first draw) * 3/8(probability of second draw which is 12/64 or 3/16 of the given scenario.
