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75%.

Explanation: if both parents are carriers than their Gametes would be Dd x Dd, resulting in DD (1/4), Dd (2/4), and dd(1/4), meaning that there is a 25% chance that they will have a child that has the disorder.

DD = A normal child that lacks the recessive gene, therefore not a carrier

Dd = A normal child that carries the recessive gene

dd = A child with the disorder + carries the gene, hence the child's future offspring will carry it as well.

Source: Self/Basic Punnet Square

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Q: What is the probability of producing a normal child by two parents who are carriers for an autosomal recessive disorder?
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