Consider the three events:
A = rolling 5, 6, 8 or 9.
B = rolling 7
C = rolling any other number.
Let P be the probability of these events in one roll of a pair of dice.
Then P(A) = P(5) + P(6) + P(8) + P(9) = 18/36 = 1/2
P(B) = P(7) = 6/36 = 1/6
and P(C) = 1 - [P(A) + P(B)] = 1/3
Now P(A before B) = P(A or C followed by A before B)
= P(A) + P(C)*P(A before B)
= 1/2 + 1/3*P(A before B)
That is, P(A before B) = 1/2 + 1/3*P(A before B)
or 2/3*P(A before B) = 1/2
so that P(A before B) = 1/2*3/2 = 3/4
The probability of rolling a six on either (or both) die is 11/36.
The probability of rolling doubles with two dice is 1 in 6, or about 0.167.
The probability is 11/36.
With one roll of three dice, the probability is 7/8.
The probability of of rolling three ones on three dice is (1 in 6)3, or 1 in 216, or about 0.004630.
The probability of rolling a six on either (or both) die is 11/36.
The probability of rolling doubles with two dice is 1 in 6, or about 0.167.
The probability of rolling either a 6 or 4 on one roll of a dice is two thirds (one sixth plus one sixth because both four and six have a probability of one sixth.
The probability is 1/36.
0% probability
The probability of rolling 12 with 2 dice is 1 in 36. The probability of not rolling 12 with 2 dice is 35 in 36.
The probability is 1/6.
The probability is 11/36.
With one roll of three dice, the probability is 7/8.
the probability is 5/6
the surface which you are rolling on, and probability.
The probability of rolling the same number on five dice is (1/6)4, or about 0.0007716.