If the only numbers to pick from are 1 through 8, how can you get a factor greater than 10?
A sum that is a factor of 6 has a greater probability.to my dick
The probability is 1/6.
The answer is 25
1 out of 2
1 out of 2
5 out of 6
Of all the six numbers on a cube, only the '5' is not a factor of 12.Probability of rolling a factor of 12 on the first cube = 5/6 .Probability of rolling a factor of 12 on the second cube = 5/6 .Probability of rolling a factor of 12 on both cubes = (5/6 x 5/6 ) = 25/36 = 694/9 %.
Spinners have different numbers of sides. Moreover, the sides are not necessarily all equal nor that they are numbered in any particular fashion. The answer depends on these factor. They have not been specified and so the question cannot be answered.
The theoretical probability of rolling something other than a factor of 6 in one roll is 2/6 or 1/3. So, the probability of rolling something other than a factor of 6 in 100 rolls is (1/3)^100 = 1.94*10-48 And therefore.the probability of rolling a factor of 6 is 1 - Prob(not a factor) = 1 - 1.94*10-48 which is incredibly close to 1.
If quality factor is greater then bandwidth will also greater
No. No number can have a factor greater than itself.
7 is an odd factor of 14 greater than 1