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What is the probability that a family with 13 children will only have 3 boys?
Wiki User
∙ 9y ago
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes.
However, if you assume that they are independent events then, given that the probability of a boy is approx 0.52, the probability of 3 boys out of 13 is 0.0273.
Wiki User
∙ 9y ago
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What is the probability that a couple with 3 children will have at least 1 girl?
The easiest way of calculating this is to find the probability that all three are boys, as this is the only arrangement that does not fit the criteria. Then work out the answer by taking this away from 1. Probability that all three are boys = 1/2 x 1/2 x 1/2 = 1/8. probability of there being at least one girl is 1 - 1/8 = 7/8 or 87.5%
What is the probability that a family of 4 would have exactly 2 girls and 2 boys?
For the sake of ease, I'm going to assume that you mean: if a family were to have four children, what is the probability of having two girls and two boys. (Note: if you actually mean a family of four, you would have to start building in the probability of single-parenthood and same-sex adoption since the parents would be included in the total family size.) One could do this problem the long way by writing out all combinations of children and identifying which one meets the criteria given in the problem and which ones do not. All Possible Combos of 4 Children GGGG BGGG GBGG GGBG GGGB BBGG BGBG BGGB GBGB GBBG GGBB GBBB BGBB BBGB BBBG BBBB Each set that matches our criteria are in bold. There are 6 "successful" pairings, out of a total of 16 possible combinations. Thus the probability is 6/16 or .375 or 37.5% that there will be two girls and two boys. That is a long way of doing this problem however and would not be as quick if we had asked about 10 children instead of only 4. Instead it is easier to think of this problem as the probability of one possible combination being correct then multiplying it by all the possible ways of writing it. You can take any possible combination of B and G as long as there are 2 Bs and 2 Gs. For this problem lets use: BBGG. The probability of this exact combination occurring is 1/16: (1/2) * (1/2) * (1/2) * (1/2) = 1/16 Remember that the probability of a certain series of independent events is equal to the each probability multiplied together. Now we must figure out all the possible ways of writing BBGG. In this case there are 6. So now 6 * (1/6) = 6/16 or 3/8 or .375 or 37.5%
What is the probability of not geeting a queen in a well shuffled deck of 52 playing cards?
If only one card is selected the probability is 12/13.If only one card is selected the probability is 12/13.If only one card is selected the probability is 12/13.If only one card is selected the probability is 12/13.
What is the probability of choosing a letter from the word probability?
Since the word "probability" contains only letters, then the probability of choosing a letter from the word "probability" is 1, i.e. it is certain to happen.
What is the or rule in probability?
Given two events, A and B, the probability of A or B is the probability of occurrence of only A, or only B or both. In mathematical terms: Prob(A or B) = Prob(A) + Prob(B) - Prob(A and B).
What is the probability that a family continue to have children until they have a boy will have more than three children?
The answer to this is 1 minus the probability that they will have 3 or fewer children. This would happen only if they had a boy as the first, second or third child. The probability they have a boy as first child is 0.5 The probability they have a boy as second is 0.25 The probability they have a boy as third is 0.125 Thus the total probability is 0.875 And so the probability they will have more than three children is 1-0.875 or 0.125
What is the probability that a family of 5 children has exactly 1 boys?
There are two main problems in answering this question. One is that the probability of a boy is 0.52 not 0.50. This is easily dealt with: use a Binomial(5, 0.52) distribution rather than Binomial(5, 0.5). However, the other probalem is much more serious: the genders of children in a family are not independent events: they depend on the parents genes as well as their age. The question can only be answered if you ignore reality. Then, the probability is 0.1563 (approx).
In a family with two children you know that one child is a girl What is the probability the second child is a girl?
There is only one answer and that is 50-50.
What is the probability that a couple with 3 children will have at least 1 girl?
The easiest way of calculating this is to find the probability that all three are boys, as this is the only arrangement that does not fit the criteria. Then work out the answer by taking this away from 1. Probability that all three are boys = 1/2 x 1/2 x 1/2 = 1/8. probability of there being at least one girl is 1 - 1/8 = 7/8 or 87.5%
Will an offspring show a recessive trait if only one of its parent has the gene for that trait?
A family tree is a great idea, but the science is based on probability. The probability that a recessive trait will show up in a family is 25% if both parents are carriers. In order for a recessive trait to show up in a person, he/she must inherit a copy of the recessive trait from both parents. If one parent is recessive, let's say "rr" and the other parent is a carrier, say "Rr", the probability is 50%. If both parents are recessive, the probability is 100% (rr x rr). If neither parent carries the trait the probability is 0% (RR x RR). BUT, this only tells you what MIGHT happen. We all know that the probability of having a boy is 50:50, but we all know families of all boys. So it would be interesting to see if the probability works out in your family. If you do a search on the web for "genetics" or "probability and genetics" you will get plenty of hits. vanhoeck
What is the probability that a family of 4 would have exactly 2 girls and 2 boys?
For the sake of ease, I'm going to assume that you mean: if a family were to have four children, what is the probability of having two girls and two boys. (Note: if you actually mean a family of four, you would have to start building in the probability of single-parenthood and same-sex adoption since the parents would be included in the total family size.) One could do this problem the long way by writing out all combinations of children and identifying which one meets the criteria given in the problem and which ones do not. All Possible Combos of 4 Children GGGG BGGG GBGG GGBG GGGB BBGG BGBG BGGB GBGB GBBG GGBB GBBB BGBB BBGB BBBG BBBB Each set that matches our criteria are in bold. There are 6 "successful" pairings, out of a total of 16 possible combinations. Thus the probability is 6/16 or .375 or 37.5% that there will be two girls and two boys. That is a long way of doing this problem however and would not be as quick if we had asked about 10 children instead of only 4. Instead it is easier to think of this problem as the probability of one possible combination being correct then multiplying it by all the possible ways of writing it. You can take any possible combination of B and G as long as there are 2 Bs and 2 Gs. For this problem lets use: BBGG. The probability of this exact combination occurring is 1/16: (1/2) * (1/2) * (1/2) * (1/2) = 1/16 Remember that the probability of a certain series of independent events is equal to the each probability multiplied together. Now we must figure out all the possible ways of writing BBGG. In this case there are 6. So now 6 * (1/6) = 6/16 or 3/8 or .375 or 37.5%
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the family is a "family of procreation", the goal of which is to produce, enculturate and socialize children. However, producing children is not the only function of the family
In Egypt what did the children do in school?
Most children didn't attend school. Noble children were tutored and it was only boys who got an education.
What is dyad family?
A dyad family is a family composing only of a husband and a wife without children.
What is a no children family?
Is a type of family that consist only with a wife and a husband with no kids.
In a classroom the students are 11 boys and 1 girl if one student is selected at random find the probability that the student is a girl?
There is only one girl out of 12 students so the probability that the girl is selected is 1/12.
What were children's jobs in ancient china?
The role of children in Ancient China was to help the family. Only wealthy boys were educated. The boys helped their father at his trade. Usually they were farmers and worked out in the fields. The girls stayed inside and helped their mother in the kitchen and taking care of children smaller than them.
