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What is the probability that a couple with 3 children will have at least 1 girl?
Wiki User
∙ 12y ago
The easiest way of calculating this is to find the probability that all three are boys, as this is the only arrangement that does not fit the criteria. Then work out the answer by taking this away from 1. Probability that all three are boys = 1/2 x 1/2 x 1/2 = 1/8. probability of there being at least one girl is 1 - 1/8 = 7/8 or 87.5%
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∙ 12y ago
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What is the probability that a couple with three children will have at least one girl?
The individual probability that a child born will be female is 50% or 0.5.Using this we can calculate the probability that at least one of the children will be female by:calculating the probability that none of the children will be female and then subtracting this from 1.The probability that all the children are male is therefore 0.53 = 0.5 * 0.5 * 0.5 = 0.125.Thus the answer is 1 - 0.125 = 0.875 = 87.5%
What is the probability that a couple with four children have atleast one girl?
There are 2 ways to do this problem. 1. Go to a Binomial Distribution Table where n = 4 (4 children) and P=0.5(50% probability of a girl). Probability of at least 1 girl = 1 - probability of no girls. From Binomial Distribution Table n = 0 probability is .0625. So, 1 - 0.0625 = .9375 = probability of at least 1 girl. 2. The other way is to list all the possible ways to have 4 children and count the number of ways at least 1 girl exists divided by the total number of ways to have 4 children. There are 42 ways to have 4 children, all 16 listed below: bbbb bbbg bbgb bgbb gbbb bbgg bggb ggbb gbbg gbgb bgbg bggg gggb ggbg gbgg gggg Since 15 of the 16 have at least 1 girl, the Probability of at least 1 girl = 15/16 = 0.9375, the same answer as above.
If a couple has had 3 boys and wants to have a girl what is their probability of having a girl?
These events are independent; so the probability of a girl is 0.5.
What is the probability that a couple will have 4 boys and 1 girl?
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes. However, if you assume that they are independent events then, given that the probability of a boy is approx 0.52, the probability 4 boys and 1 girl out of 5 children is 0.1724 approx.
Find the probability that in a family of 4 children will be a at least 1 boy b At least 1 boy and 1 girl Assume that the probability of a male birth is 12?
http://answerboard.cramster.com/statistics-and-probability-topic-5-292446-0.aspx
What is the probability that a couple with three children will have at least one girl?
The individual probability that a child born will be female is 50% or 0.5.Using this we can calculate the probability that at least one of the children will be female by:calculating the probability that none of the children will be female and then subtracting this from 1.The probability that all the children are male is therefore 0.53 = 0.5 * 0.5 * 0.5 = 0.125.Thus the answer is 1 - 0.125 = 0.875 = 87.5%
What is the probability that a couple with four children have atleast one girl?
There are 2 ways to do this problem. 1. Go to a Binomial Distribution Table where n = 4 (4 children) and P=0.5(50% probability of a girl). Probability of at least 1 girl = 1 - probability of no girls. From Binomial Distribution Table n = 0 probability is .0625. So, 1 - 0.0625 = .9375 = probability of at least 1 girl. 2. The other way is to list all the possible ways to have 4 children and count the number of ways at least 1 girl exists divided by the total number of ways to have 4 children. There are 42 ways to have 4 children, all 16 listed below: bbbb bbbg bbgb bgbb gbbb bbgg bggb ggbb gbbg gbgb bgbg bggg gggb ggbg gbgg gggg Since 15 of the 16 have at least 1 girl, the Probability of at least 1 girl = 15/16 = 0.9375, the same answer as above.
What is the probability of a couple having four children in the following order girl girl girl boy?
It is not possible to answer the question because:the total number of children that the couple had is not known;the gender of the child depends [mainly] on the father, and is not 0.5;the gender of each child is not independent of the gender of previous children.
If a couple has had 3 boys and wants to have a girl what is their probability of having a girl?
These events are independent; so the probability of a girl is 0.5.
What is the probability that a couple will have 4 boys and 1 girl?
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes. However, if you assume that they are independent events then, given that the probability of a boy is approx 0.52, the probability 4 boys and 1 girl out of 5 children is 0.1724 approx.
Find the probability that in a family of 4 children will be a at least 1 boy b At least 1 boy and 1 girl Assume that the probability of a male birth is 12?
http://answerboard.cramster.com/statistics-and-probability-topic-5-292446-0.aspx
What is the probability that they will have at least one girl if a couple plans to have 6 children?
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes.However, if you assume that they are independent events then, given that the probability of a girl is approx 0.48, thenProb(at least one girl out of 6 children) = 1 - Prob(no girls out of 6 children)= 1 - Prob(6 boys out of 6 children)= 1 - 0.526 = 0.9809There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes.However, if you assume that they are independent events then, given that the probability of a girl is approx 0.48, thenProb(at least one girl out of 6 children) = 1 - Prob(no girls out of 6 children)= 1 - Prob(6 boys out of 6 children)= 1 - 0.526 = 0.9809There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes.However, if you assume that they are independent events then, given that the probability of a girl is approx 0.48, thenProb(at least one girl out of 6 children) = 1 - Prob(no girls out of 6 children)= 1 - Prob(6 boys out of 6 children)= 1 - 0.526 = 0.9809There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes.However, if you assume that they are independent events then, given that the probability of a girl is approx 0.48, thenProb(at least one girl out of 6 children) = 1 - Prob(no girls out of 6 children)= 1 - Prob(6 boys out of 6 children)= 1 - 0.526 = 0.9809
If a couple wants to have two children what is the probability that the first will be a girl and the second will be a boy?
Assuming the chances of having a boy and having a girl are equal (50/50), there are 4 possible outcomes from having 2 children. BOY-BOY, or GIRL-GIRL, or BOY-GIRL, or GIRL-BOY. Since each outcome is of equal probability it means there's a 25% chance the first will be a girl and the second will be a boy.
What is the probability of a couple having a girl if they have 2 boys?
50/50
What is the probability of a couple having a girl?
It depends on the couples' genes. Also, at present the probability of a girls is approx 0.48
What is the probability of a couple giving birth to five girls in a row?
Probability of girl, assumed to be 0.5. Therefore, probability of 5 girls is 0.5^5 or 0.03125.
Four children that is probality at least two are girls?
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes. However, if you assume that they are independent events then, given that the probability of a girl is approx 0.48, the probability of 2 or more girls is 0.6617.
