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What is the probability that a family of four children has at least 1 boy?
1 in 2
What is the probability that a family with 4 children would have at least 1 boy?
1/4
Find the probability that in a family of 4 children will be a at least 1 boy b At least 1 boy and 1 girl Assume that the probability of a male birth is 12?
http://answerboard.cramster.com/statistics-and-probability-topic-5-292446-0.aspx
At least one child in a family with two children is a boy the the probability that both children are boys?
There is no simple answer.First of all, the probability of boys is 0.517 not0.5.Second, the probabilities are not independent.If you choose to ignore these important facts, then the answer is 2/3.
What is the probability that a couple with three children will have at least one girl?
The individual probability that a child born will be female is 50% or 0.5.Using this we can calculate the probability that at least one of the children will be female by:calculating the probability that none of the children will be female and then subtracting this from 1.The probability that all the children are male is therefore 0.53 = 0.5 * 0.5 * 0.5 = 0.125.Thus the answer is 1 - 0.125 = 0.875 = 87.5%
What is the probability of a couple having at least four girls if they have six children?
3 out of 7
What is the probability that a family of four children has at least 1 boy?
1 in 2
What is the probability that a family with 4 children would have at least 1 boy?
1/4
Find the probability that in a family of 4 children will be a at least 1 boy and 3 girls?
There is no simple answer to the question because children's genders are not independent events. They depend on the parents' ages and their genes. However, if you assume that they are independent events then, given that the probability of a boy is approx 0.52, the answer is 0.2331.
Find the probability that in a family of 4 children will be a at least 1 boy b At least 1 boy and 1 girl Assume that the probability of a male birth is 12?
http://answerboard.cramster.com/statistics-and-probability-topic-5-292446-0.aspx
Four children that is probality at least two are girls?
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes. However, if you assume that they are independent events then, given that the probability of a girl is approx 0.48, the probability of 2 or more girls is 0.6617.
At least one child in a family with two children is a boy the the probability that both children are boys?
There is no simple answer.First of all, the probability of boys is 0.517 not0.5.Second, the probabilities are not independent.If you choose to ignore these important facts, then the answer is 2/3.
What is the probability that a couple with three children will have at least one girl?
The individual probability that a child born will be female is 50% or 0.5.Using this we can calculate the probability that at least one of the children will be female by:calculating the probability that none of the children will be female and then subtracting this from 1.The probability that all the children are male is therefore 0.53 = 0.5 * 0.5 * 0.5 = 0.125.Thus the answer is 1 - 0.125 = 0.875 = 87.5%
What are the odds that they have at least one daughter and one son if a family have 2 children?
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes.However, if you assume that they are independent events then, given that the probability of a boy is approx 0.52, the probability of a daughter and a son in two children is approx 0.4994
What is the probability that a couple with four children have atleast one girl?
There are 2 ways to do this problem. 1. Go to a Binomial Distribution Table where n = 4 (4 children) and P=0.5(50% probability of a girl). Probability of at least 1 girl = 1 - probability of no girls. From Binomial Distribution Table n = 0 probability is .0625. So, 1 - 0.0625 = .9375 = probability of at least 1 girl. 2. The other way is to list all the possible ways to have 4 children and count the number of ways at least 1 girl exists divided by the total number of ways to have 4 children. There are 42 ways to have 4 children, all 16 listed below: bbbb bbbg bbgb bgbb gbbb bbgg bggb ggbb gbbg gbgb bgbg bggg gggb ggbg gbgg gggg Since 15 of the 16 have at least 1 girl, the Probability of at least 1 girl = 15/16 = 0.9375, the same answer as above.
What is the probability that a family of four children has at least 2 girls?
Going by the assumption that the probability of a child being a girl is 1/2, and that the events are independent, then the probabilities of different numbers of girls are as follows: P(0 girls) = 1/2 ^ 4 = 1/16 P(1 girl) = 4 * (1/2) * (1/2 ^ 3) = 1/4 P(2 girls) = 6 * (1/2 ^ 2) * (1/2 ^ 2) = 3/8 P(3 girls) = 4 * (1/2 ^ 3) * (1/2) = 1/4 P(4 girls) = 1/2 ^ 4 = 1/16 Therefore the probability of at least 2 girls = 3/8 + 1/4 + 1/16 = 11/16
What is the probability that they will have at least one girl if a couple plans to have 6 children?
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes.However, if you assume that they are independent events then, given that the probability of a girl is approx 0.48, thenProb(at least one girl out of 6 children) = 1 - Prob(no girls out of 6 children)= 1 - Prob(6 boys out of 6 children)= 1 - 0.526 = 0.9809There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes.However, if you assume that they are independent events then, given that the probability of a girl is approx 0.48, thenProb(at least one girl out of 6 children) = 1 - Prob(no girls out of 6 children)= 1 - Prob(6 boys out of 6 children)= 1 - 0.526 = 0.9809There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes.However, if you assume that they are independent events then, given that the probability of a girl is approx 0.48, thenProb(at least one girl out of 6 children) = 1 - Prob(no girls out of 6 children)= 1 - Prob(6 boys out of 6 children)= 1 - 0.526 = 0.9809There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes.However, if you assume that they are independent events then, given that the probability of a girl is approx 0.48, thenProb(at least one girl out of 6 children) = 1 - Prob(no girls out of 6 children)= 1 - Prob(6 boys out of 6 children)= 1 - 0.526 = 0.9809
