Use the entire excerpt of your printable table of random numbers, shown below, to estimate the answer to this question: What is the probability that a group of five random digits will contain at least three even digits? (Zero is considered an even digit.)
46370 55170 53480 49126 89212 75292 67291 88241 37808 38154
Express your answer as a fraction using the slash ( / ) bar. Reduce fractions to their lowest terms.
9/10
9/10
1-365/[(365-6)*365^6] = 1 Is this O.K ?
The probability that three F2 seeds chosen from Mendel's study group will have at least one yellow seed is 63/64. It would be very rare to get three green seeds.
7 women in a group of 11 people 7/11
The probability density function of a random variable can be either chosen from a group of widely used probability density functions (e.g.: normal, uniform, exponential), based on theoretical arguments, or estimated from the data (if you are observing data generated by a specific density function). More material on density functions can be found by following the links below.
9/10
Approx 0.0287
Birthdays are not uniformly distributed over the year. Also, if you were born on 29 February, for example, the probability would be much smaller. Ignoring these two factors, the probability is 0.0082
(4!*5!)/9! = .0079
Using the hypergeometric distribution, the answer is 2114/3003 = 0.7040
Pairs
Quadruplets
1-365/[(365-6)*365^6] = 1 Is this O.K ?
The probability that three F2 seeds chosen from Mendel's study group will have at least one yellow seed is 63/64. It would be very rare to get three green seeds.
7 women in a group of 11 people 7/11
The probability of choosing 2 girls at random from group of 25 students of which10 are girls and 15 are boys is:P( 2 girls) = (10/25)∙(9/24) = 3/20 = 0.15 = 15%
A decimal with a continuously repeating digits or group of digits