The probability of choosing 2 girls at random from group of 25 students of which
10 are girls and 15 are boys is:
P( 2 girls) = (10/25)∙(9/24) = 3/20 = 0.15 = 15%
To find the probability that the second student chosen is a boy given that the first student chosen is a boy, we first note that there are 22 students total (13 girls and 9 boys). If the first student chosen is a boy, there will then be 8 boys and 13 girls remaining, making a total of 21 students left. Therefore, the probability that the second student is a boy is the number of remaining boys (8) divided by the total remaining students (21), which gives us a probability of ( \frac{8}{21} ).
4/8 x 3/5
12/21 or 4/7
I am not going to help you cheat in math class!!!!!!!!!!!!!
1/35
The ratio of girls to total students is 15:25, or 3:5. Three out of five students are girls so there would be a 60% probability that a girl would be chosen; a 2 out of 5 chance, or 40% probability that a boy would be chosen.
The probability is 15/25 = 3/5
The probability is 15/25 = 3/5
4/8 x 3/5
If the choice is unbiased, the change is 14/(10+14). If the chooser prefers choosing boys, the probability is 0.
13 out of 20
4 in 7 chance
1-30
3-7
12/21 or 4/7
The probability is the number of girls divided by the number of students, so 12/22, or 6/11
Oh, dude, let me break it down for you. So, if you have 17 girls and 10 boys in the class, the probability of selecting a girl is like the number of girls divided by the total number of students. So, it's 17 girls out of 27 students, which simplifies to about 63%. Cool, right?