The probability that one die will not be a 3 is 5/6
The probability that all will not be 3 is ((5/6)4)
If you roll 4 dice, there are 5 possible outcomes (for this problem).
There will be NO 3's, there will be one 3, there will be two 3's. there will be three 3's, or, there will be four 3's. Add all possible probabilities = 1. At least one meanse either 1,2,3, or 4 3's but NOT one.
So the prob of at least one = total prob - prob of NO
1- (5/6)4 = 1 - 625/1296
= 671/1296 <-- answer
When a tetrahedral die is rolled, it will rest with three faces upwards. If the die is numberd from 1 to 4. therefore the sum of the upward facing numbers on 1 die is at least 6 and so for two dice, the minimum is 12. That being the case, the probability is 0.
It is 0.3125
On a normal 6 sided dice the probability of rolling any number is 1/6.When we want a 3 AND then a 4 we multiply the probabilities together.So P(3 then 4) = 1/6 x 1/6 = 1/36
The probability of rolling snake eyes on any one throw is 1 in 36. The probability of NOT rolling a snake eyes is 35 in 36. The only outcome here which we do not desire is that in which a non-snake eye roll occurs four times in a row, therefore, we take (35/36)^4 to find the probability of NEVER getting a snake eyes, and then subtract that answer from 1 to get the chances for any outcome WITH at least one pair of snake eyes. The chances are 10.66% of getting at least one snake eyes in four rolls.
2/6 or 1/3 or 0.3333.
If using regular dice, the probability is 0 since the minimum sum from four dice is 4.
(1 in 6)3 or (1 in 216) or about 0.004630.
The probability is 1/2.
The probability of rolling a dice with the letters "D," "I," "C," and "E" on all four sides is 1 in 1,296.
When a tetrahedral die is rolled, it will rest with three faces upwards. If the die is numberd from 1 to 4. therefore the sum of the upward facing numbers on 1 die is at least 6 and so for two dice, the minimum is 12. That being the case, the probability is 0.
If one die is constrained to be a 4, then the probabilities rest with the other die. A 7 in total, then, means that the other die is a 3 or higher. The probability of a three or higher is 4 in 6, or 2 in 3.
It is 0.3125
The probability of rolling a three or a four (meaning one roll, and either number would be counted a "success") is 1/3. This is because the probability of rolling a three is 1/6, the probability of rolling a four is 1/6, and if you are good with either possibility, then the combined probability is 1/6+1/6 = 1/3.
There are 36 possible combinations. Eleven of them have at least one four in it. That means it is 11 over 36, which is a 30.55% chance.
If we are thinking of getting a '6', here are the odds. Wth one dice, its 1 in 6. So,with two dice its 1 in 216 with three dice its 1 in 7776 with four dice its 1 in 279936 with five dice its a huge 1 in 10077696
The answer depends on how many times in total the dice are rolled. As the total number of rolls increases, the probability rolling a 6 and 4 three times in a row increases towards 1.
If you keep rolling the die, the probability is 1. If you require a 3 and a 4 in the first two rolls, the answer is (1/6)*(1/6) = 1/36