The answer depends on how many times in total the dice are rolled. As the total number of rolls increases, the probability rolling a 6 and 4 three times in a row increases towards 1.
The probability of rolling an odd number is 3/6 (or rather, 1/2), so the probability of rolling an odd number three times in a row is 1/2^3 is 1/8 or 12.5%.
When rolling a single die, the probability of rolling a five is ( \frac{1}{6} ). To find the probability of rolling a five three times in a row, you multiply the individual probabilities together: ( \left(\frac{1}{6}\right)^3 = \frac{1}{216} ). Therefore, the probability of rolling a five on one die three times in a row is ( \frac{1}{216} ) or approximately 0.00463.
The probability of rolling a 3 on a six-sided die in a single roll is 1/6. When rolling the die three times, the probability of getting at least one 3 can be calculated using the complement: first, find the probability of not rolling a 3 in three rolls, which is (5/6)³. Subtract this value from 1 to find the probability of rolling at least one 3 in three attempts.
There are two possibilities for rolling three once, so the probability of this even is 2/36 or 1/18. Since each roll is an independent event, the total probability is: P(rolling three three times) = (1/18)3 = 1/5832
50% chance
The probability of rolling an odd number is 3/6 (or rather, 1/2), so the probability of rolling an odd number three times in a row is 1/2^3 is 1/8 or 12.5%.
When rolling a single die, the probability of rolling a five is ( \frac{1}{6} ). To find the probability of rolling a five three times in a row, you multiply the individual probabilities together: ( \left(\frac{1}{6}\right)^3 = \frac{1}{216} ). Therefore, the probability of rolling a five on one die three times in a row is ( \frac{1}{216} ) or approximately 0.00463.
The probability of rolling a six is one in six. The probability of rolling three consecutive sixes is one in 216. (1/6 x 1/6 x 1/6 = 1/216)
The probability is 1/6 x 5=5/12
The probability of rolling a 3 on a six-sided die in a single roll is 1/6. When rolling the die three times, the probability of getting at least one 3 can be calculated using the complement: first, find the probability of not rolling a 3 in three rolls, which is (5/6)³. Subtract this value from 1 to find the probability of rolling at least one 3 in three attempts.
Assuming that the die is a "normal" one (it has the numbers 1 to 6 and that it is fair), then the probability of rolling six three times in a row is 1/6*1/6*1/6 = 1/216 = 0.00463 The probability of rolling six three times in a row eventually is 1 (ie a certainty).
1 out of 100
There are two possibilities for rolling three once, so the probability of this even is 2/36 or 1/18. Since each roll is an independent event, the total probability is: P(rolling three three times) = (1/18)3 = 1/5832
1/8
50% chance
Probability is a number between 0 and 1. The probability of an event cannot be 12.
the chances of rolling doubles once is 1 in 6; 3 times in a row it is 1 in 216. It does not make any difference after how many times you rolled the dice before.