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What is the probability that if 4 letters are typed with repetition allowed all 4 will be vowels?
It is (5/26)4 = 625/456,976 = 0.00137 approx.
What is probability if repeated events?
When an event is repeated, the probability of it occurring is squared. For instance, if an outcome had the probability of 1/4, then the outcome happening twice would have a probability of 1/16. Note, however, that this does not mean that the second event has different probabilities. That particular outcome will always be 1/4, regardless of anything that happened before it.
What is the probability of drawing a vowel from the word mathematics?
You have a total of 11 letters in "mathematics" and you have 4 vowels (a,e,a,i) so the probability of drawing a vowel is 4/11. In other words if you were to consider the vowel's to be 1's and the consonants 2's. What is the probability of drawing a "1". There would be 4 1's and 7 2's. It would be 4/11
What is the probability of getting exactly three heads when you flip a coin four times?
If it is a fair coin, the probability is 1/4.If it is a fair coin, the probability is 1/4.If it is a fair coin, the probability is 1/4.If it is a fair coin, the probability is 1/4.
One letter is randomly selected from the word math and a second letter is randomly selected from the word jokes what is the probability that both letters are vowels?
Word 1) 'math' has one vowel letter among a total of 4 letters. The probability of randomly selecting the vowel letter 'a' is P(v) = 1/4. Word 2) 'jokes' has two vowel letters among a total of 5 letters. The probability of randomly selecting a vowel letter is P(v) = 2/5. The probability of randomly selecting a vowel letter from the first word and a vowel letter from the second word is: P(v1,v2) = 1/4 (2/5) = 2/20 = 1/10 = 0.10 = 10.0%
What is the probability that if 4 letters are typed with repetition allowed all 4 will be vowels?
It is (5/26)4 = 625/456,976 = 0.00137 approx.
What is probability if repeated events?
When an event is repeated, the probability of it occurring is squared. For instance, if an outcome had the probability of 1/4, then the outcome happening twice would have a probability of 1/16. Note, however, that this does not mean that the second event has different probabilities. That particular outcome will always be 1/4, regardless of anything that happened before it.
If a code contains 4 letters and 2 numbers how many possible outcomes are there?
If the numbers and letters can be repeated then there are 45,697,600 possible outcomes. If the letters and numbers can not be repeated there are 32,292,000 possible outcomes.
What is the probability of writing correct addresses to 4 letters to be posted?
1/6
What is the probability of Wednesday or a day with 6 letters?
It is 4/7.It is 4/7.It is 4/7.It is 4/7.
What A license plate consists of 2 letters followed by 4 digits letters and digits can be repeated. Find the probability that your new license plate begins with a vowel and ends with a multiple of 3.?
Independent events, so P(both)=(5/26)(4/10)=0.07692307692. The 4/10 comes from the fact that 0, 3, 6, and 9 are the 4 digits that are multiples of 3.
If a letter is chosen at random from the word perseverance What is the probability that the letter chosen is E?
4 because in word perseverance we have 4 letters E
What is the no of linear arrangements of the four letters in CALL is?
To find the number of linear arrangements of the letters in "CALL," we need to consider the repetitions of letters. The word "CALL" has 4 letters where 'L' appears twice. The formula for arrangements of letters with repetitions is given by ( \frac{n!}{p1! \times p2! \times \ldots} ), where ( n ) is the total number of letters and ( p1, p2, \ldots ) are the frequencies of each repeated letter. Therefore, the number of arrangements is ( \frac{4!}{2!} = \frac{24}{2} = 12 ). Thus, there are 12 distinct arrangements of the letters in "CALL."
If you have 26 cards each labeled with a letter of the alphabet. What is the probability of drawing a card that contains one of the letters in the word 'MATH'?
If the card is drawn at random, then the probability is 2/13.
How many different ways can the letter MEMBERS be arranged?
If none of the letters were repeated, the answer would be 7!. However, the letters M & E are repeated. So, we need to divide the 7! by 2! twice to account for the two letters repeated twice. The solution is: 7! / (2! * 2!). This written out is: (7*6*5*4*3*2*1)/(2*1*2*1) or 1260.
How many 4 letter codes are there if letters are not repeated?
If letters cannot be repeated, then there are 26 options for the first letter. There are then 25 options for the second letter. There are then 24 options for the third letter, and 23 for the fourth. This means that in total there are 26x25x24x23 options for the code. 26x25x24x23 = 358,800. Thus, there are 358,800 possible 4 letter codes.
What is the probability of drawing a vowel from the word mathematics?
You have a total of 11 letters in "mathematics" and you have 4 vowels (a,e,a,i) so the probability of drawing a vowel is 4/11. In other words if you were to consider the vowel's to be 1's and the consonants 2's. What is the probability of drawing a "1". There would be 4 1's and 7 2's. It would be 4/11
